3 years ago

Ar + by=c What does x equal ?

Mathematics

1 answer:

Alinara [238K]3 years ago

7 0

Answer: a= −by+c /r

Step-by-step explanation:

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What’s the until rate for 3 and 2/3 feet per 11/60

Aneli [31]

Answer:

11/3 divides by 60/11 = 660/33 = 20

Step-by-step explanation:

3 0

3 years ago

Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5

Fynjy0 [20]

Answer:

a(6) = 37.97

Step-by-step explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

a(n) = 5*r^(n - 1).

Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97

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2 years ago

Please help with this questions. I’ve waisted over 100 points trying to get answers for one assignment just because the only peo

Scrat [10]

Y
-7
-4
-1
2
5

(X,Y)
(-2,-7)
(-1,-4)
(0,-1)
(1,2)
(2,5)

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B144%7D%7B25%7D%20" id="TexFormula1" title=" {x}^{

ss7ja [257]

Answer:

x²=144/25

x=±12/5

Step-by-step explanation:

Hope it helps u

4 0

3 years ago

After robbing a bank in dodge city, a robber gallops off at 14 mi/h. 20 minutes later, the marshall leaves to pursue the robber

Morgarella [4.7K]

For this case we have to write the equation of the position of each one.

We have then:

For the robber:

$r = 14t$

For the marshall :

$r = 16 (t- (\frac{20}{60}))$

$r = 16 (t-\frac{1}{3})$

By the time the marshall reaches the robber we have:

$14t = 16 (t-\frac{1}{3})$

From here, we clear the time.

We have then:

$16t - 14t = \frac{16}{3}$

$2t = \frac{16}{3}$

$t =\frac{8}{3}$

$t = 2.7 h$

Answer:

it takes the marshall to catch up to the robber about 2.7 hours.

4 0

3 years ago