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3 years ago

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How many atoms are in 5.2 miles of aluminum

1 answer:

Rashid [163]3 years ago

6 0

Answer:

How many atoms are in 6.5 moles of zinc? 6.5 moles. 6.02 x 10. 23 atoms = 3.9 x 10. 24 ... 55.8g. 1 mole. 6. What is the mass of 0.250 moles of aluminum?

Explanation:

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pantera1 [17]

Answer:

Option A. Double Replacement

Explanation:

A double displacement reaction is a kind of reaction in which there is an exchange of the ions of the two reactants to form a different products. In the equation, K in KOH displaces H in H3PO4 to form K3PO4 and also, the H combines with OH to form water.

H3PO4+3KOH -> K3PO4+3H20

4 0

3 years ago

Is PH3 polar or nonpolar

Andru [333]

Answer:

polar

Explanation:

8 0

3 years ago

Read 2 more answers

Explain the solute and the solvent in a solution

romanna [79]

Answer:

a solute is a substance that is dissolved in the solvent (liquid)

a solvent is a substance that dissolves a solute (solid)

a solution is the mixture of both the solute and solvent forming uniform mixture

5 0

3 years ago

Which equation shows how to calculate how many grams (g) of KCI would be

Semenov [28]

Answer:

C or D

Explanation:

Hope it helped a little bit

3 0

3 years ago

If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc

hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $Al_2O_3$ = $\frac{16.9\times 1000g}{102g/mol}=165.7moles$

moles of $NaOH$ = $\frac{57.4\times 1000g}{40g/mol}=1435moles$

moles of $HF$ = $\frac{57.4\times 1000g}{20g/mol}=2870moles$

As 1 mole of $Al_2O_3$ reacts with 6 moles of $NaOH$

166 moles of $Al_2O_3$ reacts with = $\frac{6}{1}\times 166=996$ moles of $NaOH$

As 1 mole of $Al_2O_3$ reacts with 12 moles of $HF$

166 moles of $Al_2O_3$ reacts with = $\frac{12}{1}\times 166=1992$ moles of $HF$

Thus $Al_2O_3$ is the limiting reagent.

As 1 mole of $Al_2O_3$ produces = 2 moles of cryolite

166 moles of $Al_2O_3$ reacts with = $\frac{2}{1}\times 166=332$ moles of cryolite

Mass of cryolite $(Na_3AlF_6)$ = $moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg$

Thus 69.72 kg of cryolite will be produced.

8 0

3 years ago