Group 11 Melting point 1064.18°C, 1947.52°F, 1337.33 K
Period 6 Boiling point 2836°C, 5137°F, 3109 K
Block d Density (g cm−3) 19.3
Atomic number 79 Relative atomic mass 196.967
State at 20°C Solid Key isotopes 197Au
Electron configuration [Xe] 4f145d106s1 CAS number 7440-57-5
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The answer is D. energy of activation increase
Answer:
No
Explanation:
One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.
When one gram phosphorus and 6 gram of iodine react they gives 8.234 g
ram of PI₃ .
Given data:
Mass of phosphorus = 1 g
Mass of iodine = 6 g
Mass of PI₃ = ?
Solution:
Chemical equation:
P₄ + 6I₂ → 4PI₃
Number of moles of P₄:
Number of moles = Mass /molar mass
Number of mole = 1 g / 123.9 g/mol
Number of moles = 0.01 mol
Number of moles of I₂:
Number of moles = Mass /molar mass
Number of moles = 6 g / 253.8 g/mol
Number of moles = 0.024 mol
Now we will compare the moles of PI₃ with I₂ and P₄.
I₂ : PI₃
6 : 4
0.024 :
4/6×0.024 = 0.02
P₄ : PI₃
1 : 4
0.01 : 4 × 0.01 = 0.04 mol
The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.
Mass of PI₃ = moles × molar mass
Mass of PI₃ = 0.02 mol × 411.7 g/mol
Mass of PI₃ = 8.234 g
We have the compound: KSCN, Potassium thiocyanate, in an aqueous solution.
The dissociated reaction of the salt:
KSCN (aq) => K+ + SCN-
It has 2 ions. One of them is the potassium ion, K+ (cation) and the other one is the thiocyanate ion, SCN- (anion).
Answer:
K+, the potassium ion
SCN-, the thiocyanate ion
