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3 years ago

PLZZ HELP ASAPPPJKSOWLSOWOLWKSKW

Chemistry

2 answers:

Minchanka [31]3 years ago

4 0

I’m pretty the answer would be continental slope. :)
I really hope this helps.

PolarNik [594]3 years ago

3 0

I can confirm it is 100% the continental slope.

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How many grams of water can be produced in the combination of

mel-nik [20]

If 14 grams of hydrogen reacted with 24.7 grams of oxygen 27.7875 grams of water will be formed.

Explanation:

2H2+O2----------->2H2O.

From the above equation, we can say that 4g of Hydrogen will react with 32 g of oxygen.

In this question, Hydrogen is in excess amount.

32 g of Oxygen will react with = 4 g of H2.

Therefore 24.7g of Oxygen will react with =24.7x4/32= 3.0875 g H2.

The remaining 10.9125g of H2 will be left unreacted.

Therefore the amount of water formed=(24.7+3.0875)=27.7875 g

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3 years ago

Why a person bitten by a snake can not drink alcohol

AfilCa [17]

Alcoholic liquors are harmful to persons bitten by venomous snakes." The alcohol acts first as a stimulant, speeding up the circulation, quickly distributing the poison through the body. When the effect wears off it becomes a depressant, lowering the victim's resistance,

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3 years ago

Water has a specific heat of 4.186 J/g*C. How much energy would be required to raise the temperature of 10 g of water by 10 C?

Sladkaya [172]

Energy(heat) required to raise the temperature of water : 418.6 J

<h3>Further explanation </h3>

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Specific heat of water = 4.186 J/g*C.

∆T(raise the temperature) : 10° C

mass = 10 g

Heat required :

$\tt Q=m.c.\Delta T\\\\Q=10\times 4.186\times 10\\\\Q=418.6~J$

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3 years ago

2 FONS

stiv31 [10]

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4) = F1/4

7 0

3 years ago

calculate the mass of calcium phosphate and the mass of sodium chloride that could be formed when a solution containing 12.00g o

Leviafan [203]

Answer : The mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

Explanation : Given,

Mass of $Na_3PO_4$ = 12.00 g

Mass of $CaCl_2$ = 10.0 g

Molar mass of $Na_3PO_4$ = 164 g/mol

Molar mass of $CaCl_2$ = 111 g/mol

Molar mass of $NaCl$ = 58.5 g/mol

Molar mass of $Ca_3(PO_4)_2$ = 310 g/mol

First we have to calculate the moles of $Na_3PO_4$ and $CaCl_2$ .

$\text{Moles of }Na_3PO_4=\frac{\text{Given mass }Na_3PO_4}{\text{Molar mass }Na_3PO_4}$

$\text{Moles of }Na_3PO_4=\frac{12.00g}{164g/mol}=0.0732mol$

and,

$\text{Moles of }CaCl_2=\frac{\text{Given mass }CaCl_2}{\text{Molar mass }CaCl_2}$

$\text{Moles of }CaCl_2=\frac{10.0g}{111g/mol}=0.0901mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

From the balanced reaction we conclude that

As, 3 mole of $CaCl_2$ react with 2 mole of $Na_3PO_4$

So, 0.0901 moles of $CaCl_2$ react with $\frac{2}{3}\times 0.0901=0.0601$ moles of $Na_3PO_4$

From this we conclude that, $Na_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $CaCl_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$ and $Ca_3(PO_4)_2$

From the reaction, we conclude that

As, 3 mole of $CaCl_2$ react to give 6 mole of $NaCl$

So, 0.0901 mole of $CaCl_2$ react to give $\frac{6}{3}\times 0.0901=0.1802$ mole of $NaCl$