I would suppose it is false because conduction is the movement of heat between two objects that are in contact.
<span>The amount of
protons is equal to the number of electrons of a chemical element. The atomic
number of an element also determines the number of the protons it contains.
The number of protons is also the same number of electrons. Protons are positively charged, electrons are
negatively charged. To get the number of neutrons, all you need is to deduct
the number of the atomic mass or mass number from the atomic number. Potassium has 19
protons, therefore has 19 electrons as well. The atomic mass of Potassium is
39. So, the number of neutrons Potassium has is 20. </span>
Potassium
Atomic
number: 19
Protons: 19
Electrons: 19
Atomic Mass:
39
Neutron: 20
Nitrogen
Atomic
number: 7
Protons: 7
Electrons: 7
Atomic Mass:
14.007
Neutrons: 7
Oxygen
Atomic
Number: 8
Protons: 8
Electrons: 8
Atomic Mass:
15.99
Neutrons: 8
Answer:
1: 38
2: 39
3: 40
4: 41
Explanation:
The mass in amu is the weight of the neutrons and protons in the element. The mass number is the number neutrons and protons you have in an element. Both neutrons and protons have a weight of 1 amu. Since you can't have a decimal of a subatomic particle, you have to round to the nearest whole number.
Answer: Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.
<h3>Answer:</h3>
Na (atomic no. 11) reacts with cl (atomic no. 17) to become stable. In the reaction, Na will <u>give up one electron</u>, while cl will <u>accept on electron</u>.
<h3>Explanation:</h3>
NaCl is formed by Na⁺ cation and Cl⁻ anion as follow,
Oxidation of Na;
Na → Na⁺ + 1 e⁻
In this step sodium looses one electron due to less ionization energy as the resulting Na⁺ ion has attained a stable noble gas configuration of Neon (i.e. 1s², 2s², 2p⁶).
Reduction of Cl₂;
Cl₂ + 2 e⁻ → 2 Cl⁻
In this step each Chlorine atom accepts one electron and forms Chloride ion (Cl⁻). Again the driving force for this step is attaining the noble gas configuration of Argon (i.e. 1s², 2s², 2p⁶, 3s², 3p⁶).
Crystal Lattice formation is as follow,
Na⁺ + Cl⁻ → NaCl
