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Sever21 [200]
3 years ago
9

How do simple distillation and fractional distillation differ?

Chemistry
1 answer:
netineya [11]3 years ago
5 0
Fractional distillation<span> is essentially the same as </span>simple distillation<span>except that a fractionating column is placed between the boiling flask and the condenser. The fractionating column is usually filled with glass or plastic beads. These beads improve the separation between the liquids being </span>distilled<span>.</span>
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How many grams of As2S3 are in 3.25 moles?
laiz [17]

Answer:

Explanation:

Molar mass of As2S3= {75(2) + 32(3)}

= 150 + 96 = 246g/mol

Amount = 3.25mole

And

Amount = mass/ molar mass

mass = amount × molar mass

Mass = 3.25 × 246

mass = 799.5g

6 0
3 years ago
According to the reaction represented by the unbalanced equation above, how many moles of so2(g) are required to react completel
melomori [17]
2SO₂ + O₂ = 2SO₃

n(O₂)=1 mol

n(SO₂)=2n(O₂)

n(SO₂)=2 mol
6 0
3 years ago
Mass = 25g, Volume = 5mL. What is the density? *
Fantom [35]

Answer:

5ml

Explanation:

m/v

25/5=5

means 25÷5=5

6 0
3 years ago
Nault 25000L 250 our = 25000L 15040 8. How many grams of CaCl2 are needed to make 150.0 mL of a 0.500 M CF solution? (Note: CaCl
yuradex [85]

Answer:

You need 8,324 g of CaCl₂ yo make this solution

Explanation:

Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.

To know the grams of CaCl₂ it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:

0,1500 L × \frac{0,500 mol}{L} = 0,075 CaCl₂ moles

Now, with the molar mass of CaCl₂ you will obtain the necessary grams, thus:

0,075 CaCl₂ moles  × \frac{110,98 g}{mol} = 8,324 g of CaCl₂

So, you need <em>8,324 g of CaCl₂</em> to make 150,0 mL of a 0,500M solution

I hope it helps!

3 0
3 years ago
There are three isotopes of X element (X):
Nutka1998 [239]

Answer:

Average atomic mass = 17.5 amu.

Explanation:

Given data:

X-17 isotope = atomic mass17.2 amu, abundance:78.99%

X-18isotope =  atomic mass 18.1 amu, abundance 10.00%

X-19isotope = atomic mass:19.1 amu, abundance: 11.01%

Average atomic mass of X = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100

Average atomic mass =  1358.628 + 181 +210.291 / 100

Average atomic mass  = 1749.919 / 100

Average atomic mass = 17.5 amu.

8 0
3 years ago
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