2 years ago

How do simple distillation and fractional distillation differ?

1 answer:

5 0

Fractional distillation is essentially the same as simple distillationexcept that a fractionating column is placed between the boiling flask and the condenser. The fractionating column is usually filled with glass or plastic beads. These beads improve the separation between the liquids being distilled.

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When can the park be reopen to people and animals. Explain calculations and answers. Explain the concept.

julsineya [31]

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Explanation:

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2 years ago

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The equilibrium concentrations of the reactants and products are [ HA ] = 0.260 M [HA]=0.260 M , [ H + ] = 2.00 × 10 − 4 M [H+]=

ValentinkaMS [17]

Answer:

pKa of the acid HA with given equilibrium concentrations is 6.8

Explanation:

The dissolution reaction is:

HA ⇔ H⁺ + A⁻

So at equilibrium, Ka is calculated as below

Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260

= 15.38 x 10⁻⁸

Hence, by definition,

pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813

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3 years ago

When NADH donates two electrons to ubiquinone during respiration, ubiquinone isa. reduced.b. oxidized.c. phosphorylated.d. aerob

olga nikolaevna [1]

Reduced ... more electrons gain is a reduction

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3 years ago

Which of the following have the lowest density solids rocks liquids gases

denis23 [38]

Answer:

gases

Explanation:

because the solid (steel) is the most dense, the gas (air) is the least dense, and the density of the liquid (water) is in between.

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3 years ago

What is the correct equation for the reaction quotient of the following reaction? 2Fe3+(aq) + Zn(s) ⇌ 2Fe2+(aq) + Zn2+(aq)

Ira Lisetskai [31]

Explanation:

A reaction quotient is defined as the ratio of concentration of products over reactants raised to the power of their stoichiometric coefficients.

A reaction quotient is denoted by the symbol Q.

For example, $2Fe^{3+}(aq) + Zn(s) \rightleftharpoons 2Fe^{2+}(aq) + Zn^{2+}(aq)$

The reaction quotient for this reaction is as follows.

Q = $\frac{[Fe^{2+}]^{2}[Zn^{2+}]}{[Fe^{3+}]^{2}}$

[Zn] will be equal to 1 as it is present in solid state. Therefore, we don't need to write it in the reaction quotient expression.

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2 years ago