Answer:
Explanation:
volume of ball bearing = 4/3 π r³
= 4/3 x 3.14 x 1.5³
= 14.13 cc.
if D be the density of steel , weight of the ball bearing
= 14.13 x D x g
For the first case , water will be displaced to keep it floating
weight of displaced water will be equal to weight of steel
weight of displaced water = 14.13 Dg
mass of displaced water = 14.13 D
volume of displaced water = mass / density of water
= 14.13 D / d ; (where d is density of water) .
Now when the steel ball bearing is dipped in water , it will displace water equal to its volume only and it will be drowned
its volume = 14 .13 cc
14.13 D / d > 14.13 ( because D/d is more than one , since D > d )
volume of water displaced in first case is greater
water level will go up higher in first case .
Hence in the second case water level will go down .
Same will happen in case of 25 kg steel .
