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3 years ago

11

Aman tosses a jart upward with a velocity of 14.1 m/s a 60° angle

1 answer:

crimeas [40]3 years ago

8 0

Answer:

hold on let me check my answer

Explanation:

You might be interested in

A woman steps in front of a child to keep him from running off. which term best describes this example? negative work positive w

lana [24]

Answer:

negative force

Explanation:

Here woman is applying the force to stop the child or to prevent him from running.

Here we know that the force applied by the woman is opposite to the motion of child but here the child is not displaced by this applied force but the child is only prevented his running.

So here the work done by the woman is zero as there is no displacement by this force.

But here we can say that the the force of woman is against the motion of child so here this force is opposite force and hence it is termed as negative force here.

so correct answer will be

negative force

4 0

3 years ago

Read 2 more answers

How is buoyancy used in the real world?

JulsSmile [24]

Answer:

to mack boats float

Explanation:

without it the boats will sink to the bottom

7 0

2 years ago

Read 2 more answers

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 350 newtons stretches a sprin

Bingel [31]

Answer:

Explanation:

350 N force stretches the spring by 30 cm

spring constant K = 350 / 0.30 = (350 / 0.3) N / m

To calculate work done by a spring force we proceed as follows

spring force when the spring is stretched by x = Kx

This force is variable so work done by it can be calculated by integration

Work done by it in stretching from x₁ to x₂

W = ∫ F dx

= ∫ Kx dx with limit from x₁ to x ₂

= 1/2 K ( x₂² - x₁² )

Putting the given values of x₁ = 0.50 m , x₂ = 0.8 m

Work done

= 1/2 x (350 / 0.3)x ( 0.80² - 0.50² )

= 227.50 J

5 0

2 years ago

15m/s is how many Newtons

GuDViN [60]

147.09975 newton meters per second

5 0

2 years ago

Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.00×104 Pa . Assum

cestrela7 [59]

Answer:

$T_{2}=278.80 K$

Explanation:

Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.

$(\frac{V_{1}}{V_{2}})^{\gamma -1} = \frac{T_{2}}{T_{1}}$ .

Now, let's use the ideal gas equation to the initial and the final state:

$\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}$

Let's recall that the term nR is a constant. That is why we can match these equations.

We can find a relation between the volumes of the initial and the final state.

$\frac{V_{1}}{V_{2}}=\frac{T_{1}p_{2}}{T_{2}p_{1}}$

Combining this equation with the first equation we have:

$(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}$

$(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}$

Now, we just need to solve this equation for T₂.

$T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}$

Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.

Here,

$p_{2}=8.00\cdot 10^{4} Pa \\p_{1}=1.01\cdot 10^{5} Pa\\ T_{1}=298 K\\ \gamma=1.40$

Finally, T2 will be:

$T_{2}=278.80 K$

6 0

3 years ago