All categories

4 years ago

0.0003711 in scientific notation is

1 answer:

5 0

So we want to know how to write the number 0.0003711 in scientific notation. Scientific notation is the way scientist write very big and very small numbers with the powers of 10. It is used to simplify writing of those numbers. So 0.0003711 is 3.711*10^-4.

You might be interested in

Analisis morfologico palabra yo gane el primer premio

ale4655 [162]

Answer:

eres raro jajaja pero eres realmente genial y ordenado espero que esto te ayude jajaja

Explanation:

5 0

3 years ago

Momentum usually has the symbol p It is a vector, What is the correct way to

Nadya [2.5K]

Answer:

Add an arrow above the symbol p to show it is a vector. Sometimes it is italicized in textbooks.

Explanation:

6 0

3 years ago

Can someone please help me with these 2 questions

jok3333 [9.3K]

1. Answer: 7.75 seconds
Explanation: 76-14=62 metres
62/8=7.75 seconds

2. Answer: 2.5 seconds
Explanation: 28-18=10 metres
10/4=2.5 seconds

5 0

4 years ago

A 200kg bumper car moving 3 m/s collides head on with a 392kg bumper car moving 6m/s. After impact, the larger car continues tra

Maru [420]

Answer:

the final speed of the smaller car is 5.624 m/s

Explanation:

Given;

mass of the small car, m₁ = 200 kg

initial velocity of the small car, u₁ = 3 m/s

mass of the larger car, m₂ = 392 kg

initial velocity of the larger car, u₂ = 6 m/s

final velocity of the larger car, v₂ = 1.6 m/s

let the direction of the larger car be positive

let the direction of the smaller car be negative

Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

200(-3) + 392(6) = 200v₁ + 392 x 1.6

-600 + 2352 = 200v₁ + 627.2

1752 = 200v₁ + 627.2

1752 - 627.2 = 200v₁

1124.8 = 200v₁

v₁ = 1124.8/200

v₁ = 5.624 m/s

Therefore, the final speed of the smaller car is 5.624 m/s

7 0

3 years ago

I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, a

drek231 [11]

Answer:

P₂ = 1.22 kPa

Explanation:

This problem can be solved using the equation of state:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

$\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}$

7 0

3 years ago