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boyakko [2]
3 years ago
14

Write the point-slope form of the line that passes through (6,1) and is perpendicular to a line with a slope of -3. include all

of your work in your final answer.
Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

(y-1)=\frac{1}{3}(x-6)

Step-by-step explanation:

The equation of the line in point-slope form is:

(y-y_1)=m(x-x_1)

Where m is the slope and (x_1,y_1) is a point of the line.

The slopes of two perpendicular lines are opposite reciprocal, then the other slope is:

m=\frac{1}{3}

Substitute the slope and the given point into the equation, then you obtain:

(y-1)=\frac{1}{3}(x-6)

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Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
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Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

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In math, the "product of" represents multiplication, so we multiply the 2 numbers.

32 x 1/4 = 8

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