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boyakko [2]
3 years ago
14

Write the point-slope form of the line that passes through (6,1) and is perpendicular to a line with a slope of -3. include all

of your work in your final answer.
Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

(y-1)=\frac{1}{3}(x-6)

Step-by-step explanation:

The equation of the line in point-slope form is:

(y-y_1)=m(x-x_1)

Where m is the slope and (x_1,y_1) is a point of the line.

The slopes of two perpendicular lines are opposite reciprocal, then the other slope is:

m=\frac{1}{3}

Substitute the slope and the given point into the equation, then you obtain:

(y-1)=\frac{1}{3}(x-6)

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What is the additive version of the complex number -8+3i
Lana71 [14]

Answer:

8-3i

Step-by-step explanation:

The complex additive inverse is the number we need to add so that we get zero.  It is the negative of the number.

a + bi is –(a + bi) = –a – bi.

a+bi + (-a+-bi) = a-a + bi-bi = 0

The complex additive invers of -8+3i is

-(-8+3i)

Distribute the negative

8 -3i

6 0
3 years ago
Evaluate plzzz help am giving brainliest
posledela

Answer:

-4a/-8 +-12a

Step-by-step explanation:

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2 years ago
What's the pattern of 160,80,40,20,10​
Brrunno [24]
The pattern is that each number is decreasing by half
3 0
3 years ago
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10. In the figure below, ABCD is a square. DEFC, BCGH and AEFB are all
zysi [14]

Answer:

a) As sides of squares are always equal.

So,

BC=CD

2b+CF=a+b

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6 0
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URGENT!!<br> The difference between the roots of the quadratic equation x2−12x+q=0 is 2. Find q
Tasya [4]

Answer:

-24

Step-by-step explanation:

substitute by 2

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8 0
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