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boyakko [2]
2 years ago
14

Write the point-slope form of the line that passes through (6,1) and is perpendicular to a line with a slope of -3. include all

of your work in your final answer.
Mathematics
1 answer:
Hitman42 [59]2 years ago
4 0

Answer:

(y-1)=\frac{1}{3}(x-6)

Step-by-step explanation:

The equation of the line in point-slope form is:

(y-y_1)=m(x-x_1)

Where m is the slope and (x_1,y_1) is a point of the line.

The slopes of two perpendicular lines are opposite reciprocal, then the other slope is:

m=\frac{1}{3}

Substitute the slope and the given point into the equation, then you obtain:

(y-1)=\frac{1}{3}(x-6)

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Let x represent the amount invested at 6%. Then x+10000 is the amount invested at 8%. The total income from the two investments is the sum of the products of the amount invested and the interest rate:

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Given:

The expression is

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We have,

\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=

The expression \sqrt[3]{48} can be written as

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