Write the point-slope form of the line that passes through (6,1) and is perpendicular to a line with a slope of -3. include all

Question

3 years ago

14

of your work in your final answer.

1 answer:

Hitman42 [59] · Answer 1 · 2022-08-13T03:23:13+03:00

Answer:

$(y-1)=\frac{1}{3}(x-6)$

Step-by-step explanation:

The equation of the line in point-slope form is:

$(y-y_1)=m(x-x_1)$

Where m is the slope and $(x_1,y_1)$ is a point of the line.

The slopes of two perpendicular lines are opposite reciprocal, then the other slope is:

m= $\frac{1}{3}$

Substitute the slope and the given point into the equation, then you obtain:

$(y-1)=\frac{1}{3}(x-6)$