Question
What mass of Al₂O₃ form is produced if 25.00 g of aluminum (al) is reacted completely?, knowing the molar mass of Al₂O₃ is 102 g/mol?
Atomic mass of Al =27 and O = 16
The molar mass of Al₂O₃ = 102.
Mass of aluminium in 102 g of Al₂O₃ = 54 g
54 g Al => 102 g Al₂O₃
25g Al => x g Al₂O₃
x = 25*102/54 = 47.2 g Al₂O₃
To solve more questions on molar mass check here:
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I will try to do it but not more than 70.4
First, we write the reaction equation:
NiCO₃ + 2HBr → NiBr₂ + H₂CO₃
Now, writing this in ionic form:
NiCO₃ + 2H⁺ + 2Br⁻ → NiBr₂ + 2H⁺ + CO₃⁻²
(NiCO₃ is insoluble so it does not dissociate in to ions very readily)
Overall equation:
NiCO₃ + 2Br⁻ → NiBr₂ + CO₃⁻²
Answer:
A. It can travel through empty space
Explanation:
Unlike sound it light can travel at an empty space or vacuum.
Hope it helps <3 and Amen.
First calculate mass of sodium hydrogen phosphate (Na₂HPO₄) needed for solution:
n(Na₂HPO₄) = V(Na₂HPO₄) · c(Na₂HPO₄)
n(Na₂HPO₄) = 0,3 dm³ · 0,2 mol/dm³
n(Na₂HPO₄) = 0,06 mol
m(Na₂HPO₄) = 0,06 mol · 142 g/mol
m(Na₂HPO₄) = 8,52 g.
Measure that mass on scale using spoon and beaker. Than dissolve salt in beaker with distilled <span>water and pour that solution in volumetric flask (size 300 mL), pour </span>distilled water to graduation<span> mark.</span>
