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lesantik [10]
2 years ago
13

Which of the following accurately describes rill erosion?

Chemistry
1 answer:
worty [1.4K]2 years ago
4 0

Answer:

C. Runoff from heavy rainfall forms narrow, shallow channels.

Explanation:

Erosion is the gradual washing away of the top layer of the soil or earth on which plant grows. There are three main types of erosion which are:

1. Sheet erosion

2. Gully erosion

3. Rill erosion

Rill erosion occurs when a soil layer is gradually being washed away by narrow stream channels called streamlets on the surface. After a heavy downpour, the streamlets facilitates the movement of water on the ground surface and in turn, earth materials are worn away.

When these streamlets becomes deeper, they form gullies. Gullies results into gully erosion.

When runoff removes soil and loose sediment in thin layers it is called sheet erosion.

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Which of the following are compounds (select all that apply)
olga2289 [7]

Answer:

KNO2, KBr

Explanation:

Chemical compounds are any substance composed of identical molecules consisting of atoms of two or more chemical elements. So NO2 and KBr are compounds, Br2 and Fe are not.

3 0
2 years ago
Beginning with commercial grade hydrochloric acid, 1.00 • 10^2 mL of a 12.4 M HCl is added to water to bring the total volume if
MatroZZZ [7]
Concentration=mass/volume.

This should help.
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2 years ago
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

By the Nersnt equation:

E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

E°cell = 0 - (0.0592/2)*log(0.23/0.87)

E°cell = 0.017V

3 0
3 years ago
Describe three factors that could limit the growth of the prairie dog population
alexira [117]

Answer:

Changes in environment, food source changes and disease?

Explanation:

I dont know what the answer choices are

5 0
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Flocabulary circulation
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