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lesantik [10]
3 years ago
13

Which of the following accurately describes rill erosion?

Chemistry
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

C. Runoff from heavy rainfall forms narrow, shallow channels.

Explanation:

Erosion is the gradual washing away of the top layer of the soil or earth on which plant grows. There are three main types of erosion which are:

1. Sheet erosion

2. Gully erosion

3. Rill erosion

Rill erosion occurs when a soil layer is gradually being washed away by narrow stream channels called streamlets on the surface. After a heavy downpour, the streamlets facilitates the movement of water on the ground surface and in turn, earth materials are worn away.

When these streamlets becomes deeper, they form gullies. Gullies results into gully erosion.

When runoff removes soil and loose sediment in thin layers it is called sheet erosion.

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Scientists think the moon was formed when
lubasha [3.4K]

Answer:

A meteor hit earth they think the moon is created from debris from earth but really God created it UwU

Explanation:

5 0
3 years ago
The mass of an object is 1,000 g. It has a volume of 100 mL. What is the density of the object? D= mass/volume
maxonik [38]

Answer:

10 g/ml

Explanation:

divide mass by volume means divide 1000 by 100 and your answer will be 10

4 0
3 years ago
A. what is the hybridization of the central atom in cse2?
elixir [45]

The orbital hybridization of the central carbon atom in CSe2 is sp.

In chemical bonding, atomic orbitals may be combined to form appropriate hybrid orbitals suitable for bonding. The orbitals that combine during hybridization must be close enough in energy.

In the compound Cse2, carbon is the central atom bonded to two selenium atoms. The carbon atom in CSe2 is sp hybridized.

Learn more about orbital hybridization:  brainly.com/question/1869903

4 0
2 years ago
An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm
frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

 xA= 0.34, yA= 0.55

ii)      0.50 = 0.55 nv + 0.34 nL

     Therefore, nV =    0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii)  ρA= 0.791 g/cm3 and,  ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

Therefore, percentage of vapour volume = 88747 / (88747+63.48) = 99.9 %

3 0
3 years ago
Please help. balance this equation
Nuetrik [128]

Answer:

k=2

ci=2

o=6

k=2

ci=2

o=6

Explanation:

4 0
3 years ago
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