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BlackZzzverrR [31]
3 years ago
10

chemist is using 387 mL of solution of acid in water if 13.3 of the solution is acid how many milliliters of acid are there roun

d answer to nearest tenth
Chemistry
1 answer:
Greeley [361]3 years ago
6 0

Answer:

V acid = 51.471 mL

Explanation:

  • %v/v = [(compoud volumen)/(solution volume)]×100

∴ V solution = 387 mL

∴ %v/v = 13.3 %

compund volume:

⇒ (V acid)/( V sln) = 0.133

⇒ V acid = (0.133)(387 mL)

⇒ V acid = 51.471 mL

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Using the curve which letter represents efficiency?
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Answer:

point A , B and C

Explanation:

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Determine the formulas for these ionic compounds. copper(I) bromide: copper(I) oxide: copper(II) bromide: copper(II) oxide: iron
joja [24]

Answer:

copper(I) bromide: CuBr

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copper(II) oxide: CuO

iron(III) bromide: FeBr₃

iron(III) oxide: Fe₂O₃

lead(IV) bromide: PbBr₄

lead(IV) oxide: PbO₂

I hope this helped you! Brainliest would be greatly appreciated.

4 0
3 years ago
Which of the following statement is not true?
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3 years ago
Why is it called endogenous process
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7 0
3 years ago
Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip
avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

       q = 600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}

         = 0.0378 m^{3}/s&#10;

    Diameter = 8 in \times \frac{0.0254 m}{1 in}

                   = 0.2032 m

Relation between area and diameter is as follows.

           A = \frac{\pi}{4} \times D^{2}

               = \frac{3.14}{4} \times (0.2032 m)^{2}

               = 0.785 x 0.2032 x 0.2032

               = 0.0324 m^{2}

Also,     q = A × V

or,         V = \frac{q}{A}

                = \frac{0.0378 m^{3}/s}{0.0324 m^{2}}

                = 1.166 m/s

As, viscosity of water = 1 cP = 10^{-3} Pa-s

Density of water = 1000 kg/m^{3}

Therefore, we will calculate Reynolds number as follows.

 Reynolds number = \frac{D \times V \times density}{viscosity}

                                 = \frac{0.2032 m \times 1.166 m/s  \times 1000}{10^{-3}}  

                                = 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0
3 years ago
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