Answer: I believe it is B
Answer:
The simulated 1H NMR spectrum for ethyl acetate is shown in the drawing attached.
Explanation:
To construct this NMR it is necessary to identify the essential components that can produce resonance peaks.
Two main groups can be identified, the acetyl group containing a sub-component (CH3) capable of producing a resonance peak, and the ethyl group containing two components (CH2 and CH3) each of which can produce on its own its own resonance peak.
Answer:
2.7 °C.kg/mol
Explanation:
Step 1: Calculate the freezing point depression (ΔT)
The normal freezing point of a certain liquid X is-7.30°C and the solution freezes at -9.9°C instead. The freezing point depression is:
ΔT = -7.30 °C - (-9.9 °C) = 2.6 °C
Step 2: Calculate the molality of the solution (b)
We will use the following expression.
b = mass of solute / molar mass of solute × kilograms of solvent
b = 102. g / (162.2 g/mol) × 0.650 kg = 0.967 mol/kg
Step 3: Calculate the molal freezing point depression constant Kf of X
Freezing point depression is a colligative property. It can be calculated using the following expression.
ΔT = Kf × b
Kf = ΔT / b
Kf = 2.6 °C / (0.967 mol/kg) = 2.7 °C.kg/mol
Answer:
6.75g of hydrogen will completely react with 54g of oxygen
Explanation:
0.869952156982 to be precise
