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djverab [1.8K]
3 years ago
10

CHEGG Consider the following reaction: LaTeX: Fe\left(CN\right)_6^{3-}+e^-\longrightarrow Fe\left(CN\right)_6^{4-}F e ( C N ) 6

3 − + e − ⟶ F e ( C N ) 6 4 − From the cyclic voltammetry data, a cathodic peak potential (Epa) of 0.271 V and an anodic peak potential (Epc) of 0.330 V was obtained. Is the reaction reversible?
Chemistry
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

E°= E°cathode- E° anode= 0.271-0.330= -0.59V

Explanation:

NB: the stoichiometry does not affect E°values,

And the more positive the E° values , the greater it's tendency to become spontaneous and hence irreversible, and the more negative the E° values the more likely to become less spontaneous and reversible, hence the above reaction is reversible

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how many moles of potassium dichromate (k2cr2o7) are required to prepare a 250-ml solution of with a concentration of 2.16 m?
Eva8 [605]

The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M  is 0.54 mol.

given that :

molarity = 2.16 M

volume = 250 mL = 0.25 L

the molarity is given as :

molarity = number of moles / volumes in L

from this we can calculate the number of moles, we get :

number of moles of K₂Cr₂O₇ = molarity × volume

number of moles of K₂Cr₂O₇ = 2.16 × 0.25

number of moles of K₂Cr₂O₇ = 0.54 mol

Thus, The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M  is 0.54 mol.

To learn more about moles here

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4 0
1 year ago
Define the term macromolecule
makkiz [27]

Explanation:

a molecule containing a very large number of atoms, such as a protein, nucleic acid, or synthetic polymer.

4 0
3 years ago
What is the percentage of nitrogen in ammonium chloride (NH4Cl)?
Katena32 [7]

Answer:

25%

Explanation:

Ammonium Chloride NH4CI Fertilizer-grade NH4Cl usually contains 25% N. About two-thirds of the world capacity for manufacture of this material is located in Japan, with the remaining one-third situated in India and China.

4 0
3 years ago
Please help. it’s my last question.
ale4655 [162]
<h3>Further explanation </h3>

Given

Atomic symbol

Required

Atomic composition

Solution

Atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Number of protons and Number of Neutrons  in nucleus

Number of electrons in the shell

From the picture:

protons = 3

neutrons = 4

electrons = 3

atomic number = protons = electrons = 3

mass number = protons + neutrons = 3+4 = 7

4 0
3 years ago
How many grams of He are necessary to fill a balloon having a volume of 4.50 × 10^{3} mL to a pressure of 1.14 × 10^{3} torr at
lana [24]

The mass in grams of He are necessary to fill a balloon having a volume of 4.50×10³ mL to a pressure of 1.14×10³ torr at 25.0ºC is 1.104 grams.

<h3>How do we calculate the grams from moles?</h3>

Mass (W) in grams from moles (n) will be calculated by using the below equation:
n = W/M, where

M = molar mass

Moles of helium gas will be calculated by using the ideal gas equation:

PV = nRT, where

R = universal gas constant = 62.363 L.torr / K.mol

P = pressure of gas = 1.14×10³ torr

V = volume of gas = 4.50×10³ mL = 4.50 L

n = moles of gas = ?

T = temperature = 25.0ºC = 298 K

On putting these values on the ideal gas equation, we get

n = (1140)(4.5) / (62.363)(298) = 5130 / 18584

n = 0.276 moles

Now we convert this moles into mass by using the first equation as:

W = (0.276mol)(4g/mol) = 1.104 g

Hence required mass of helium gas is 1.104 grams.

To know more about ideal gas equation, visit the below link:

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5 0
2 years ago
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