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3 years ago

Before using glassware in the lab, it is important to _______.

Chemistry

2 answers:

Luden [163]3 years ago

8 0

Answer:

D All of these

Explanation:

hope this helped

zhuklara [117]3 years ago

4 0

D all of these causes everything needs to be in check

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Which of the following statements is not correct?

velikii [3]

To answer the question above, multiply the given number of moles by the molar masses.

(A) (0.20 mole) x (32 g / 1 mole) = 6.4 grams O2
(B) (0.75 mole) x (62 g / 1 mole) = 46.5 grams H2CO3
(C) (3.42 moles) x (28 g / 1 mole) = 95.7 grams CO
(D) (4.1 moles) x (29.88 g / 1 mole) = 122.508 g Li2O

The answer to the question above is letter D.

4 0

3 years ago

Iron fluoride (FeF2) dissociates according to the following equation:

melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

$Kps = \frac{[product]^x}{[reagent]^y}$

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of $Fe^{+2}$ is necessary 2 mols of $F^-$ , so if we call "x" the molar concentration of $Fe^2$ , for $F^-$ we will have 2x, so:

$Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L$

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

Fe = 55.8 g/mol

F = 19 g/mol

FeF2 = Fe + 2xF = 55.8 + 2x19 = 93.8 g/mol

So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0

3 years ago

Define the term macromolecule

makkiz [27]

Explanation:

a molecule containing a very large number of atoms, such as a protein, nucleic acid, or synthetic polymer.

4 0

2 years ago

Two different compounds are obtained by combining nitrogen with oxygen. the first compound results from combining 46.7 g of n wi

kondaur [170]

<span>First:

46.7 g of N with 53.3 g of O,

=> mass ratio O to N = 53.3 / 46.7 = 1.1413

Second

17.9 g of N and 82.0 g of O.

mass ratio of O to N = 82.0 / 17.9 = 4.5810

Third

Ratio of the mass ratio of O to N in the second compound to the mass ratio of O to N in the first compound =

= 4.5810 / 1.1413 = 4.013 ≈ 4

Answer: 4
</span>

8 0

3 years ago

Whoever answers correctly I’ll give you a Brainly

Andre45 [30]

Answer:

answer is B

Explanation:

3 0

2 years ago

Read 2 more answers