Answer:
2.7 °C.kg/mol
Explanation:
Step 1: Calculate the freezing point depression (ΔT)
The normal freezing point of a certain liquid X is-7.30°C and the solution freezes at -9.9°C instead. The freezing point depression is:
ΔT = -7.30 °C - (-9.9 °C) = 2.6 °C
Step 2: Calculate the molality of the solution (b)
We will use the following expression.
b = mass of solute / molar mass of solute × kilograms of solvent
b = 102. g / (162.2 g/mol) × 0.650 kg = 0.967 mol/kg
Step 3: Calculate the molal freezing point depression constant Kf of X
Freezing point depression is a colligative property. It can be calculated using the following expression.
ΔT = Kf × b
Kf = ΔT / b
Kf = 2.6 °C / (0.967 mol/kg) = 2.7 °C.kg/mol
Answer:
The steps for solving a numeric word problem are analyze, calculate, and evaluate. To solve a word problem, you must first determine where you are starting from (identify what is known) and where you are going (identify the unknown).
Proteins are made of carbon, hydrogen,oxygen, and nitrogen (CHON). Nucleic acids such as DNA and RNA contain carbon,hydrogen, oxygen, nitrogen, and phosphorus(CHON P). The body also needs trace amounts of other elements such as calcium,potassium, and sulfur for proper functioning of muscles, nerves, etc.
Electrical?
Hope this helps