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Jobisdone [24]
3 years ago
11

Which is the correct order for a food chain?

Chemistry
1 answer:
Zigmanuir [339]3 years ago
6 0
C because first comes the source or producer than the first eater then the second and then it decomposes
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What is the difference between a homogeneous and heterogeneous mixture?
Semmy [17]
A homogeneous mixture is made up of multiple different substances. (You can see different parts)
Ex: Cereal in milk or ice in soda

A heterogeneous mixture is a mixture that is mixed well. ( you can’t see the different parts)
Ex: Rain or air
8 0
2 years ago
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1 Ammonia, NH3, reacts with incredibly strong bases to produce the amide ion, NH2 -. Ammonia can also react with acids to produc
Charra [1.4K]

Answer:

a) ammonium ion

b) amide ion

Explanation:

The order of decreasing bond angles of the three nitrogen species; ammonium ion, ammonia and amide ion is NH4+ >NH3> NH2-. Next we need to rationalize this order of decreasing bond angles from the valence shell electron pair repulsion (VSEPR) theory perspective.

First we must realize that all three nitrogen species contain a central sp3 hybridized carbon atom. This means that a tetrahedral geometry is ideally expected. Recall that the presence of lone pairs distorts molecular structures from the expected geometry based on VSEPR theory.

The amide ion contains two lone pairs of electrons. Remember that the presence of lone pairs causes greater repulsion than bond pairs on the outermost shell of the central atom. Hence, the amide ion has the least H-N-H bond angle of about 105°.

The ammonia molecule contains one lone pair, the repulsion caused by one lone pair is definitely bless than that caused by two lone pairs of electrons hence the bond angle of the H-N-H bond in ammonia is 107°.

The ammonium ion contains four bond pairs and no lone pair of electrons on the outermost nitrogen atom. Hence we expect a perfect tetrahedron with bond angle of 109°.

5 0
3 years ago
My homework said"Solve using the standard algorithm. Check your quotient and remainder by using multiplication and addition."
Harman [31]
84 divided by 2 = 42.

2 goes into 8 four times, so there would be your 4.
 Then 2 goes into 2 one time, and there would be your 2.

You check your answer by multiplying 42 by 2, which would give you, 84.
5 0
3 years ago
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Can someone help me with this please!
pashok25 [27]
Nit<u>ITE</u><u /> is NO<u>2</u><u />
nitr<u>ATE</u><u /> is NO<u>3</u><u />
5 0
3 years ago
Complete and balance the following redox reaction in acidic solution As2O3(s) + NO3- (aq) → H3AsO4(aq) + N2O3(aq)
scoray [572]

Answer:

As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)

Explanation:

Oxidation: As_{2}O_{3}(s)\rightarrow H_{3}AsO_{4}(aq)

  • Balance As: As_{2}O_{3}(s)\rightarrow 2H_{3}AsO_{4}(aq)
  • Balance H and O in acidic medium: As_{2}O_{3}(s)+5H_{2}O(l)\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)
  • Balnce charge: As_{2}O_{3}(s)+5H_{2}O(l)-4e^{-}\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)......(1)

Reduction: NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)

  • Balance N: 2NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)
  • Balance H and O in acidic medium: 2NO_{3}^{-}(aq)+6H^{+}(aq)\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)
  • Balance charge: 2NO_{3}^{-}(aq)+6H^{+}(aq)+4e^{-}\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)......(2)

Equation (1)+Equation (2) gives-

As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)

3 0
3 years ago
Read 2 more answers
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