Step one of the Hydrogen fusion process helium a nucleus of Deuterium is formed from two protons with the emission of an antielectron and a neutrino.
The fundamental Hydrogen fusion cycle includes 4 Hydrogen nuclei and two electrons and yields a Helium nucleus, two neutrinos and six photons. The principle series phase is the stage in development where the center temperature reaches the point for the fusion to begin. in this manner, the protons of hydrogen are converted into atoms of helium.
If the star is big sufficient to fuse hydrogen atoms into helium, it's going to enter the phase that our solar is in, referred to as the primary sequence section. a celebrity will enjoy most of its existence in the major series section. At this point nuclear fusion is turning hydrogen into helium.
A star isn't always absolutely a star until it is able to fuse hydrogen into helium. before that, they are called Protostars. A protostar is fashioned as gravity begins to tug the gases together right into a ball. This process is referred to as accretion.
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Important of Grignard Reagent :
Grignard reactions are main due to their capacity to form carbon-carbon bonds. Grignard reagents are powerful bases and will react with protic compounds which makes them exceptionally valuable implement for organic synthesis.
Grignard reagents react fastly with acidic hydrogen atoms in molecules such as alcohols and water. When a Grignard reagent reacts with water, a proton return back halogen, and the product is an alkane. The Grignard reagent therefore provides a trace for transforming a haloalkane to an alkane in two steps.
When reacted with water,
RMgX + H2O -------> R-H + MgOH X
R ---- Alkyl Group
X --- Halogen
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Answer:
we need the model to answer
Explanation:
Answer:
pH = 11.60
Explanation:
When we add a base, we are increasing [OH⁻], so the pH will be totally basic.
pH of water = 7
Basic pH > 7
We are adding 2 M . 1 mL = 2 mmoles
2 mmoles of OH⁻ are contained in 501 mL of total volume.
[OH⁻] = 2 mmol / 501 mL = 3.99×10⁻³ M
- log 3.99×10⁻³ M = 2.39 → pOH
pH = 14 - pOH → 11.61
Water equilibrium
2H₂O ⇄ H₃O⁺ + OH⁻ Kw = 1×10⁻¹⁴
NaOH → Na⁺ + OH⁻
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