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iVinArrow [24]
3 years ago
11

which will feel warmer to the touch, a bucket of water at 50°C or a bathtub filled with water at 25°C

Chemistry
1 answer:
MaRussiya [10]3 years ago
6 0
The bucket of water at 50°C
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Which of the following happen because of an increase in thermal energy/temperature? (Select all that apply)
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What is relative isotopic mass
lidiya [134]

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Relative atomic mass or atomic weight is a dimensionless physical quantity defined as the ratio of the average mass of atoms of a chemical element in a given sample to the atomic mass constant. The atomic mass constant is defined as being 1/12 of the mass of a carbon-12 atom.

8 0
3 years ago
Write the symbol for the monatomic ion that has a charge of 1– and the condensed electron configuration [ne]3s23p6.
Pani-rosa [81]
<span>Answer is: the symbol is Cl.
[Ne ] 3s</span>² 3p⁶ is electric configuration of noble gas argon, neon (Ne) has10 electrons plus 6 electrons in 3s and 3p orbitals. Neutral atom of m<span>onatomic ion that has a charge of 1– has one electron less than argon, so that atom (chlorine) has 17 electrons. Charge of 1- means one electron more for ion: 17 + 1 = 18.

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3 0
3 years ago
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part of the SO2 that is introduced into the atmosphere by combustion of sulfur containing compounds ends up being converted to s
alisha [4.7K]

Answer:

5 mol.

Explanation:

Equation of the reaction

2SO2 + 2H2O + O2 --> 2H2SO4

By stoichiometry, 2 moles of SO2 reacted with 2 moles of water and 1 mole of O2 to give 2 mole of sulphuric acid.

Number of moles:

5.0 mol SO2

4.0 mol O2

20.0 mol H2O

Calculating the limiting reagent,

5 mol of SO2 * 1 mol of O2/2 mol of SO2

= 2.5 mol of O2(4 mol of O2 is present)

5 mol of SO2 * 2 mol of H2O/2 mol of SO2

= 5 mol of H2O(20 mol of H2O)

SO2 is the limiting reagent.

Therefore, number of moles of H2SO4 = 5 mol of SO2 * 2 mol of H2SO4/2 mol of SO2

= 5 mol of H2SO4.

5 0
3 years ago
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
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