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Masteriza [31]
3 years ago
12

In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of three elements. What are they?

Chemistry
1 answer:
Lyrx [107]3 years ago
5 0

Oxygen, Nitrogen and Fluorine

Explanation:

In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of the oxygen, nitrogen and fluorine.

  • Hydrogen bonding is a type of dipole - dipole attraction between two specie.
  • It is an intermolecular force of attraction.
  • This bond type forms when hydrogen is bonded to a more electronegative atom.
  • These atoms are oxygen, nitrogen and fluorine
  • These species draws the electron shared more to themselves and leaves a partial positive charge on the hydrogen and a negative charge on them.
  • The electrostatic force of attraction between the hydrogen of one molecule and the O/N/F of another molecule cause the formation of hydrogen bonds.

learn more:

Hydrogen bonding brainly.com/question/10602513

#learnwithBrainly

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Explain how balanced and unbalanced forces affect an object's motion differently.
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Newton's first law of motion is sometimes called the law of inertia. When the forces acting on an object are balanced, the object is either at rest or moving with a constant velocity. Unbalanced forces can cause an object to accelerate or decelerate. Unbalanced forces can also cause an object to change direction.
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Acid rain is a type of pollution caused mainly from
Aleksandr-060686 [28]

Answer:

im pretty sure its the second one

4 0
3 years ago
What is the empirical formula of a compound that contains 6.10 g of hydrogen and 28 g of nitrogen?
Viktor [21]

Answer:

NH₃

Explanation:

mass H = 6.10 grams

mass N = 28.00 grams

mass cpd = (6.10 + 28.00)grams = 34.10 grams

%H/100wt = (6.10/34.10)100% = 17.9% w/w

%N/100wt = (28.00/34.1)100% = 82.1% w/w

%/100wt => grams/100wt => moles => ratio => reduce => emp ratio

%H/100wt = 17.9% w/w => 17.9g => (17.9/1)moles = 17.9 moles H

%N/100wt = 82.1% w/w => 82.1g => (82.1/14)moles = 5.9 moles N

Ratio N:H => 17.9 : 5.9

Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9

=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)

3 0
3 years ago
How long would it take for a car to travel 200km if it has an aventage speed of 55 km/ hr
krek1111 [17]

Answer:

It would take 3.64 hours to travel.

Explanation:

200km with 55 per hour.

200 divided by 55 would equal 3.64.

I am dividing because to solve time would be distance/rate.

I hope this helps! :)

7 0
3 years ago
Read 2 more answers
What is the vapor pressure (in mm Hg) of a solution of 17.5 g of glucose (C6H12O6) in 82.0 g of methanol (CH3OH) at 27∘C? The va
vichka [17]

Answer:

134.8 mmHg is the vapor pressure for solution

Explanation:

We must apply the colligative property of lowering vapor pressure, which formula is: P° - P' = P° . Xm

P° → Vapor pressure of pure solvent

P' → Vapor pressure of solution

Xm → Mole fraction for solute

Let's determine the moles of solute and solvent

17.5 g . 1 mol/180 g = 0.0972 moles

82 g . 1mol / 32 g = 2.56 moles

Total moles → moles of solute + moles of solvent → 2.56 + 0.0972 = 2.6572 moles

Xm → moles of solute / total moles = 0.0972 / 2.6572 = 0.0365

We replace the data in the formula

140 mmHg - P' = 140 mmHg . 0.0365

P' = - (140 mmHg . 0.0365 - 140mmHg)

P' = 134.8 mmHg

5 0
3 years ago
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