Answer:
36.08%
Explanation:
We are given the overall formula of the compound as: CuSO4•5H2O
Now, atomic mass of the elements are;
Cu = 63.55 g/mol
S = 32.07 g/mol
O = 16 g/mol
H20 = 18.02 g/mol
Now, let's calculate the total mass of the compound:
(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol
From the above, water in the compound is 5(H20)
Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol
Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%
Percentage of water = (90.1/249.72) × 100% = 36.08%
