Answer:
A typical organic molecule that contains carbon hydrogen oxygen nitrogen and sulfur will be an amino acid.
Explanation:
Amino acid is the basic protein unit composed of the amino group, carboxylic group, and an alkyl group (which is specific for every amino acid). The R group or alkyl group is what gives the amino acid its identity. For example, the amino acid will be glycine if a Hydrogen atom is attached in place of the R group, and alanine if somehow the R group is replaced by a methyl group. Cystine is a typical example of an amino acid in which carbon, hydrogen oxygen, nitrogen, and sulfur are present. The structure of cystine is given below.
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6 electrons... 's' can hold 2..... 'd' can hold 10 and 'f' can hold 14
Answer:
The correct answer is B) electronegativities of the bonded atoms in a molecule of the compound .
Explanation:
When two atoms forming a bond differ in their electronegativities at that time bond polarity is generated
In simple words a bond will be polar when the bonding electrons are not equally shared by two atoms.As a result the atom attract the bonding electron pair towards itself gain partial negative charge and the other atom gains partial positive charge.
For HCl is a polar compound because H and Cl atom differ in their electronegativities,as a result the bonding electron pair is not shared equally by H and Cl atoms.
Answer:
solids, liquids, gases, or plasma
Explanation:
In chemistry, a chemical substance is a form of matter that has constant chemical composition and characteristic properties. It cannot be separated into components without breaking chemical bonds. Chemical substances can be solids, liquids, gases, or plasma
Answer:
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Explanation:
Step 1: Data given
Volume = 500 mL = 0.500 L
The concentration sodium sulfate = 2.104 M
Step 2: The equation
Na2SO4 → 2Na+ + SO4^2-
For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)
Step 3: Calculate the concentration of the ions
[Na+] = 2*2.104 M = 4.208 M
[SO4^2-] = 1*2.104 M = 2.104 M
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
