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vodka [1.7K]
3 years ago
11

A 31 mC charge is positioned on the x axis at x + 8 cm. Where should a -70 mC charge be placed (on the positive X-axis) to produ

ce a net electric field of zero at the origin?
Physics
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:r=12.02 cm

Explanation:

Given

q_1=31 mC=31\times 10^{-3}C

Placed at x=8 cm

q_2=-70 mc=-70\times 10^{-3} C

placed at a distance, suppose r

Electric field due to positive charge will be away from the origin and electric field due to negative charge is towards the origin

Thus net effect will be zero

E=\frac{kq}{r^2}

E_1=\frac{9\times 10^{9}\times 31\times 10^{-3}}{0.08^2}

E_2=\frac{9\times 10^{9}\times 70\times 10^{-3}}{r^2}

Equate E_1=E_2

\frac{31}{8^2}=\frac{70}{r^2}

r=8\times \sqrt{\frac{70}{31}}

r=12.02 cm

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Answer:

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Explanation:

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A small pebble and one large boulder start at the same height and begin rolling down the side of a mountain. Which object would
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P.E = mgh = K.E

So, K.E = mgh where g = acceleration due to gravity and h = height of drop

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Answer:

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On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

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6 0
3 years ago
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