Answer:
n = 1/5 and m = 3/5
Explanation:
The given quantity is :
Where
The dimension of [A] = [LT]
The dimension of [B] = [L²T⁻¹]
The dimension of [C] = [LT²]
We need to find the dimensions of n and m values.
Using dimensional analysis,
![[LT]=[L^2T^{-1}]^n[LT^2]^m\\\\\ [LT]=L^{2n}T^{-n}\times L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}](https://tex.z-dn.net/?f=%5BLT%5D%3D%5BL%5E2T%5E%7B-1%7D%5D%5En%5BLT%5E2%5D%5Em%5C%5C%5C%5C%5C%20%5BLT%5D%3DL%5E%7B2n%7DT%5E%7B-n%7D%5Ctimes%20L%5EmT%5E%7B2m%7D%5C%5C%5C%5C%5C%20%5BLT%5D%3DL%5E%7B2n%2Bm%7DT%5E%7B2m-n%7D)
Comparing both sides,
2n+m=1 ....(1)
-n+2m=1 ,.....(2)
Solving (1) and (2), we get :
n = 1/5 and m = 3/5
Hence, this is the required solution.
In order to solve this problem, we must first find out the value of each line on the number line. However, we can make this problem more simple by ignoring every interval except for the ones between 0 and 6. There are three total intervals in between 0 and 6 (including 6 and excluding 0). Therefore, we can do 6/2, and get an interval value of 2. This means that each line adds a value of 2. Since the car is only one line past zero, we only have to add one value of 2. Since 0 + 2 = 2, our final answer is C. 2.
Hope this helps!
Answer:
The rocket travelled 37km per minute
Explanation:
185÷5=37
Answer:
<h2>15 Ns</h2>
Explanation:
The impulse of an object can be found by using the formula
impulse = force × time
From the question we have
impulse = 0.5 × 30
We have the final answer as
<h3>15 Ns</h3>
Hope this helps you
