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Illusion [34]
2 years ago
12

Nzvhybprob it is really coll to do it​

Physics
1 answer:
nika2105 [10]2 years ago
6 0

Answer:

gddtufxhjdtigdtuh abi na

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A student measures the mass 8cm block of brown sugar to be 12.9g. what is the density of the brown sugar.
antoniya [11.8K]

Correction

A student measures the mass <em><u>8cm3</u></em> block of brown sugar to be 12.9g. what is the density of the brown sugar

Answer:

1.6\ g/cm^{3}

Explanation:

Density is defined as mass per unit volume of an object expressed as \rho=\frac {m}{v} where \rho is the density, m is the mass of sugar and v is the volume of the sugar. Considering that the volume is given as 8cm3 for sugar then we substitute this for v and mass of 12.9 g we substitute for g then the density will be

\rho=\frac {12.9 g}{8 cm3}=1.6125\ g/cm^{3}\approx 1.6\ g/cm^{3}

8 0
3 years ago
A delivery drone uniformly slowed down from 45 m/s to 23 m/s in a straight line over a 30-minute duration within a 16-kilometer
Neporo4naja [7]
I think it is letter A
7 0
3 years ago
An observer stands on the side of the front of a stationary train. When the train starts moving with constant acceleration, the
Zarrin [17]

To solve this problem we will use the linear motion description kinematic equations. We will proceed to analyze the general case by which the analysis is taken for the second car and the tenth. So we have to:

x = v_0 t \frac{1}{2} at^2

Where,

x= Displacement

v_0 = Initial velocity

a = Acceleration

t = time

Since there is no initial velocity, the same equation can be transformed in terms of length and time as:

L = \frac{1}{2} a t_1 ^2

For the second cart

2L \frac{1}{2} at_2^2

When the tenth car is aligned the length will be 9 times the initial therefore:

9L = \frac{1}{2} at_3^2

When the tenth car has passed the length will be 10 times the initial therefore:

10L = \frac{1}{2}at_4^2

The difference in time taken from the second car to pass it is 5 seconds, therefore:

t_2-t_1 = 5s

From the first equation replacing it in the second one we will have that the relationship of the two times is equivalent to:

\frac{1}{2} = (\frac{t_1}{t_2})^2

t_1 = \frac{t_2}{\sqrt{2}}

From the relationship when the car has passed and the time difference we will have to:

(t_2-\frac{t_2}{\sqrt{2}}) = 5

t_2 (\sqrt{2}-1) = 3\sqrt{2}

t_2= (\frac{5\sqrt{2}}{\sqrt{2}-1})^2

Replacing the value found in the equation given for the second car equation we have to:

\frac{L}{a} = \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2

Finally we will have the time when the cars are aligned is

18 \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_3^2

t_3 = 36.213s

The time when you have passed it would be:

20\frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_4^2

t_4 = 38.172

The difference between the two times would be:

t_4-t_3 = 38.172-36.213 \approx 2s

Therefore the correct answer is C.

4 0
3 years ago
Which of the following objects has kinetic energy?
kotykmax [81]

Answer:

B

Explanation:

A body has kinetic energy that is moving

5 0
3 years ago
Read 2 more answers
During a shock which lasts 10ms (0.01s), the voltage difference between the electrodes (so the drop in potential across all thre
natta225 [31]

Answer:

20000 W

Explanation:

Power: This can be defined as the rate at which energy is dissipated or used. The S.I unit of power is Watt(W).

The expression of power is given as,

P = E/t.............................. Equation 1

Where P = power, E = Energy, t = time.

Given: E = 200 J, t = 0.01 s

Substitute into equation 1

P = 200/0.01

P = 20000 W.

Hence the average power = 20000 W

5 0
3 years ago
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