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OLga [1]
2 years ago
11

At what height from the surface of the earth does the value of acceleration due to gravity be 2.45 m/s square where the radius o

f the earth is 6400 km
​
Physics
1 answer:
Citrus2011 [14]2 years ago
3 0

Answer:

Explanation: RADIUS OF EARTH = 6400X1000m =

ACC DUE GRAVITY ABOVE SURFACE OF EARTH = g' =2.45 m/s^2

ACC DUE GRAVITY ON SURFACE OF EARTH =g= 9.8 m/s^2

A/C TO FORmULA

g'/g=1-2h/Re

g'/g +2h/Re = 1

2h/Re =1- g'/g

2h= (1- g'/g)Re

2h=(1-2.45 /9.8)

6400X1000

2h = (0.75)6400X1000

2h = 4800000

h= 2400000

m

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a) See free-body diagram in attachment

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a)

The free-body diagram of a body represents all the forces acting on the body using arrows, where the length of each arrow is proportional to the magnitude of the force and points in the same direction.

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The net force is obtained as the resultant  of the net forces in the horizontal and vertical direction. However, we have:

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