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OLga [1]
1 year ago
11

At what height from the surface of the earth does the value of acceleration due to gravity be 2.45 m/s square where the radius o

f the earth is 6400 km
​
Physics
1 answer:
Citrus2011 [14]1 year ago
3 0

Answer:

Explanation: RADIUS OF EARTH = 6400X1000m =

ACC DUE GRAVITY ABOVE SURFACE OF EARTH = g' =2.45 m/s^2

ACC DUE GRAVITY ON SURFACE OF EARTH =g= 9.8 m/s^2

A/C TO FORmULA

g'/g=1-2h/Re

g'/g +2h/Re = 1

2h/Re =1- g'/g

2h= (1- g'/g)Re

2h=(1-2.45 /9.8)

6400X1000

2h = (0.75)6400X1000

2h = 4800000

h= 2400000

m

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Based on the calculation of the resultant of vector forces:

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  2. the resultant force due to the quadriceps is 1975 N. Training and strengthening the vastus medialis results in a greater force of muscle contraction.

<h3>What is the resultant force due to the quadriceps?</h3>

The resultant of more than two vector forces is given by:

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where:

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  • Fₙ is the sum of the vertical components of the forces
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  • F₃ = 600 N, θ = 90 + 15 = 105°
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<h3>What would happen if the vastus medialis was trained and strengthened to contract with 720N of force?</h3>

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