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svlad2 [7]
3 years ago
11

retta has 40 raffle tickets to sell. She is required to sell at least 15 tickets. She sells the raffle tickets for $10 each. The

amount of money Gretta makes from selling x raffle tickets is represented by a function. f(x)=10x What is the practical range of the function?
Mathematics
2 answers:
Rudiy273 years ago
8 0
It should be 400 considering raffle=x×10=400
ollegr [7]3 years ago
7 0

Answer:

<h2>[150,400]</h2>

Step-by-step explanation:

Retta has 40 raffle tickets to sell and she has to sell at least 15 tickets. So, the interval that represents this situation is [15,40], because the minimum allowed is 15 tickets, and the maximum possible is 40 tickets.

We know by given that the function that models this situation is

f(x)=10x

To find the valid range, we just need to find the values assigned to x=15 and x=40.

f(x)=10x\\f(15)=10(15)=150

f(x)10x\\f(40)=10(40)=400

Therefore, the practical range of the function is [150,400]

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5 0
3 years ago
Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found. A squirrel hid 40 nuts all together.
koban [17]

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15 nuts do not get found.

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