retta has 40 raffle tickets to sell. She is required to sell at least 15 tickets. She sells the raffle tickets for $10 each. The

Question

2 years ago

11

retta has 40 raffle tickets to sell. She is required to sell at least 15 tickets. She sells the raffle tickets for $10 each. The

amount of money Gretta makes from selling x raffle tickets is represented by a function. f(x)=10x What is the practical range of the function?

Mathematics

2 answers:

Rudiy27 · Answer 1 · 2022-08-06T21:34:08+03:00

Rudiy272 years ago

8 0

It should be 400 considering raffle=x×10=400

ollegr [7] · Answer 2 · 2022-08-06T23:24:28+03:00

Answer:

Step-by-step explanation:

Retta has 40 raffle tickets to sell and she has to sell at least 15 tickets. So, the interval that represents this situation is $[15,40]$ , because the minimum allowed is 15 tickets, and the maximum possible is 40 tickets.

We know by given that the function that models this situation is

$f(x)=10x$

To find the valid range, we just need to find the values assigned to $x=15$ and $x=40$ .

$f(x)=10x\\f(15)=10(15)=150$

$f(x)10x\\f(40)=10(40)=400$

Therefore, the practical range of the function is [150,400]