Answer:
Explanation:
Given
mass of each car
acceleration of train
Force required to pull this system
For first car
for second car
this form a pattern of the form
for (a)30 th and 31 st car tension
For 49 th and 50 th car
Answer:
-600 J
Explanation:
F₁ = 8i +29 j + 32k
F₂ = 48 i - 59 j - 22 k
F = F₁ +F₂ = 8i +29 j + 32k +48 i - 59 j - 22 k
F = 56i - 30 j + 10 k
displacement d = ( 0 - 20 )i + ( 0 - 15 )j + ( 7 -0) k
d = - 20 i - 15 j + 7 k
Work Done = F dot product d
F . d = - 56 x 20 - 30 x - 15 + 10 x 7
= - 1120 +450 + 70
= -600 J
The answer is C because its shiny
The maximum torque that can act on the loop is 7.875 N-m.
Torque:
Torque is a twisting or turning force that tends to cause rotation around an axis, which might be a center of mass or a fixed point. Torque can also be thought of as the ability of something that is rotating, such as a gear or a shaft, to overcome turning resistance.
The formula of torque:
Torque(T) = I B A
B = magnetic field of intensity
I = current =
A = area of the wire
l = length of the wire
l = 2πr
r = l/2π
A = πr²
= π(l/2π)²
= l²/4π
T = l²/4π IB
=( 1/4π) BIl²
= (1/4π) 0.30 × 150 ×× 2.20
= 7.875 N-m
Therefore the torque is 7.875 N-m.
To know more about the Torque refer to the link given below:
brainly.com/question/1691855
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