As per the third law of Newton, the force exerted by the boat over the student is equal in magnitude to the force that the student exerted on the boat.
So, calculate the force on the student using the second law of Newton, Force = mass * acceleration.
Force on the student = 60 kg * 2.0 m/s^2 = 120 N.
=> horizontal force exerted by the student on the boat = 120 N
Answer: option d. 120 N. toward the back of the boat.
Of course it is toward the back because that is where the student jumped from..
A force is changing the motion of the bus.
<h3>What is Newton's first law of motion?</h3>
Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that form unless acted upon by an external force.
The applied force on the bus in the form of brakes acts as the external force on the bus.
According to Newton's first law of motion, the external force (brakes) will change the motion of the bus.
Thus, we can conclude that a force is changing the motion of the bus.
Learn more about Newton's first law of motion here: brainly.com/question/24922261
It’s voltage can easily be modified and it allows power to be transmitted at a high voltage rate before being lowered to a smaller voltage rate to be safe.
Answer:
3) From 37 km/h to 47 km/h
Explanation:
Kinetic Energy: This is the energy posses by a body in motion. The Unit of kinetic energy is joules. And it is expressed mathematically as,
Ek = 1/2mv².................... Equation 1
ΔEk = 1/2m(v₂² - v₁²)...................... Equation 2
Where ΔEk = change in kinetic energy, m = mass of the body, v₁ = initial velocity, v₂ = final velocity of the body.
<em>Note: The mass of the car is constant in both cases.</em>
When the body accelerate from 27 kh/h to 37 km/h
ΔEk₁ = 1/2m(37²-27²)
ΔEk₁ = 1/2m(640)
ΔEk₁ = 320m J.
When The body accelerate from 37 km/h to 47 km/h
ΔEk₂ = 1/2m(37²-47²)
ΔEk₂ = 1/2m(840)
ΔEk₂ = 420m J
From the above,
ΔEk₂ > ΔEk₁.
Hence the correct option is 3) From 37 km/h to 47 km/h