The people are using a lot of electricity blow drying to many peoples hair so i would make a schedule so it dosent get to busy with costumers
The momentum of the car is 4.4x10^3 kg•m/sec
Since the ladder is standing, we know that the coefficient
of friction is at least something. This [gotta be at least this] friction
coefficient can be calculated. As the man begins to climb the ladder, the
friction can even be less than the free-standing friction coefficient. However,
as the man climbs the ladder, more and more friction is required. Since he
eventually slips, we know that friction is less than what's required at the top
of the ladder.
The only "answer" to this problem is putting lower
and upper bounds on the coefficient. For the lower one, find how much friction
the ladder needs to stand by itself. For the most that friction could be, find
what friction is when the man reaches the top of the ladder.
Ff = uN1
Fx = 0 = Ff + N2
Fy = 0 = N1 – 400 – 864
N1 = 1264 N
Torque balance
T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)
N2 = 439 N
Ff = 439= u N1
U = 440 / 1264 = 0.3481
Answer:
Clockwise and counter clockwises, depands.
Explanation:
The direction of current in a loop of wire in a magnatic field depands on the direction in which the loop is moved and the applied magnatic field.
this is determined by what is called right hand rule.
I will give one scenario, let's say that the loop is moved upwards and the applied magnatic field is into the page (if you drew the loop in 2D on a piece of paper), in this case the direction would be clockwise.