Answer:
example of adaptation in mangrove
Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.
adaptation of rainforest
Many animals have adapted to the unique conditions of the tropical rainforests.
hope this can help you
Answer:
7572 m/s
Explanation:
The force between two masses separated by a distance r is given as:
Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is 
The mass of the earth (
) is far greater than the mass of the sputnik (
). Therefore 
. The mass of the sputnik is neglected, therefore:
But F is actually centripetal acceleration, a = v²/r
The particle temperature and the valency of the atom in the particles are the two parameters that decrease with the kinetic energy of the particles in an item.
<h3>What is temperature?</h3>
Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.
Because an item possesses kinetic energy when it is moving, anything that prevents that motion will reduce the kinetic energy of the object.
A valence electron is an electron in the outermost shell associated with an atom that can experience the innovation of a chemical bond if the outer shell is not closed. Both atoms contribute one valence electron to create a shared pair.
More the valence electron more the motion of atoms results in more kinetic energy,
Hence the two factors decrease as the kinetic energy of the particles in an object will be the particle temperature and the valency of the atom in the particles.
To learn more about the temperature refer to the link;
brainly.com/question/7510619
#SPJ2
Answer:
The phase constant is 7.25 degree
Explanation:
given data
mass = 265 g
frequency = 3.40 Hz
time t = 0 s
x = 6.20 cm
vx = - 35.0 cm/s
solution
as phase constant is express as
y = A cosФ ..............1
here A is amplitude that is = 
= 
= 6.25 cm
put value in equation 1
6.20 = 6.25 cosФ
cosФ = 0.992
Ф = 7.25 degree
so the phase constant is 7.25 degree
