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Gwar [14]
4 years ago
12

A paint brush is dropped from the top of a tall ladder and free falls to the ground. What changes, if any, would be observed of

the velocity and the acceleration of the brush as it falls? Pick the two answers. The velocity increases. The velocity decreases. The velocity remains a constant value. The acceleration increases. The acceleration decreases. The acceleration remains a constant value.
Physics
1 answer:
muminat4 years ago
4 0

Answer:

Explanation:

As the paint brush is dropped from the top of a tall ladder it started free falling

i.e. velocity of brush increases as it falls down due to the acceleration provided by gravity.

We know acceleration due to gravity is the attraction experienced by the object due to earth attraction

Value of acceleration due to gravity is constant i.e. 9.8\ m/s^2

Therefore the correct choice is

velocity is increasing and acceleration is constant

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The above stress can be also approximated by a sinusoidal function (i.e. sine wave) with an average 3,811 kPa, amplitude 430 kPa
stepan [7]

Answer:

306.08 kPa

Explanation:

Given data

Average stress of first wave = 3811 kPa

amplitude of first wave ( A1 ) = 430 kPa

Frequency of first wave = 6 Hz

<u>Determine the average stress of the second sinusoidal component in kPa </u>

Amplitude of the additional wave (A2add) = \frac{A1}{2}  =  430 / 2 = 215 kPa

next we will determine the resultant amplitude of the second wave

A2 = \sqrt{A^{2} _{1} }  + A^{2} _{2add} + 2A_{1}A_{2add}  Cos\alpha

     = \sqrt{430^2+ 215^2 + 2(430*215) * cos 90}

     = \sqrt{184900 + 46225  }

     = \sqrt{231155}  = 480.79

hence the average stress of the second sinusoidal component

= \frac{2A_{2} }{\pi }

=  \frac{2 * 480.79 }{\pi }  =  306.08 kPa

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