Answer:
The Electric flux will be 
Explanation:
Given
Strength of the Electric Field at a distance of 0.158 m from the point charge is

We know that the flux of the Electric Field can be calculated by using Gauss Law which is given by

Let consider a sphere of radius 0.158 m as Gaussian Surface at a distance of 0.158 m from the point charge and Let
be the flux of the Electric Field coming out\passing through it which is given by

It can be observed that same amount of flux which is passing through the Gaussian sphere of radius 0.158 is also passing through the Gaussian sphere of radius 0.142 m at a distance of 0.142 m from its centre.
Also it can be observed that the charge inside the two Gaussian Sphere mentioned have same value so the Flux of electric field through them will also be same.
So the electric flux through the surface of sphere that has given charge at its centre and that has radius 0.142 m is 
Answer:
Part a)

Part b)

Explanation:
Part a)
In order to have same range for same initial speed we can say


so after comparing above we will have

so we have


Part b)
Time of flight for the first ball is given as



Now for other angle of projection time is given as


So here the time lag between two is given as



Answer:
v = -24.5 m/s
Explanation:
Use conservation of momentum P = m*v. Unless there are external forces involved, total momentum must be conserved.
P: momentum
m: mass
v: velocity
1. calculate the total momentum before the collision:

2. the total momentum after the collision must not change:

3. after the collision the velocity of the car is the same as the velocity of the truck:

4. combining 2. and 3.:

5. this equation only has one unknown and can be solved for v:


I’m 95% sure it’s covalent bonds.
Answer:
4
Explanation:
We know that intensity I = P/A where P = power and A = area through which the power passes through.
Now, let the initial intensity of the speaker be I₀ and its initial power be P₀. Since the intensity is increased by a factor of 4, the new intensity be I and new power be P.
So, I = P/A and I₀ = P₀/A
Now, if I = 4I₀,
P/A = 4P₀/A
P = 4P₀
Now, energy E = Pt, where t = time. So, P = E/t and P₀ = E₀/t
Substituting P and P₀ into the equation, we have
P = 4P₀
E/t = 4E₀/t
E = 4E₀
Since the energy is four times the initial energy, the energy output increases by a factor of 4.