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Mrrafil [7]
3 years ago
10

Tendons. Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke’s law. I

n laboratory tests on a particular tendon, it was found that, when a 250-g object was hung from it, the tendon stretched 1.23 cm. (a) Find the force constant of this tendon in N>m. (b) Because of its thickness, the maximum tension this tendon can support without rupturing is 138 N. By how much can the tendon stretch without rupturing, and how much energy is stored in it at that point?
Physics
1 answer:
Zolol [24]3 years ago
7 0

Answer:

Explanation:

Given

mass of object(m)=250 gm

Stretching(x)=1.23 cm

Suppose force constant to be k

then kx=mg

k\times 1.23\times 10^{-2}=250\times 10^{-3}\times 9.8

k=\frac{9.8\times 100}{4\times 1.23}

k=199.18 N/m

(b)Maximum Tension is 138 N

138=kx

x=\frac{138}{199.18}=0.692\approx 69.2 cm

Energy stored=\frac{kx^2}{2}=\frac{199.18\times (0.692)^2}{2}=47.80 J

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3 years ago
A small object carrying a charge of -4.00 nC is acted upon by a downward force of 19.0 nN when placed at a certain point in an e
Gala2k [10]

Explanation:

Given that,

Charge acting on the object, q=-4\ nC=-4\times 10^{-9}\ C

Force acting on the object, F=19\ nC=19\times 10^{-9}\ C (in downward direction)

(a) The electric force acting in the electric field is given by :

F=qE

E is the electric field

E=\dfrac{F}{q}

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E = 4.75 N/C

The direction of electric field is as same as electric force. But it is negative charge. So, the direction of electric field is in upward direction.

(b) The charge on the proton is, q=1.6\times 10^{-19}\ C

The force acting on the proton is :

F=qE

F=1.6\times 10^{-19}\times 4.75

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If the charge on the proton is positive, the force on the proton is in upward direction.

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8 0
3 years ago
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Answer:

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Explanation:

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Answer:

True.

Explanation:

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