Hello Esmeralda
Specific heat is measured in Joules per g times degree Celsius.
I hope this helps!
<span>Use the cosine rule to solve for the distance the wind pushed them to the east and because this all happened in an hour, you can say they travelled this distance per hour.
+-130 km due east which means the wind speed was +-130km/h.
So for example i used a^2=b^2+c^2-2bc(cos75) b will be the distance they travelled and c= 135cos75=35km now all you do is substitute in and you will get your distance that the wind pushed them to the east and because it was an hour of travel the distance as said before will be per hour. </span>
Answer:
Force on front axle = 6392.85 N
Force on rear axle = 8616.45 N
Explanation:
As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels
Now we know that
now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle
so we can write torque balance about its center of mass
now from above equation
now we have
now the other force is given as
A) Using:
2as = v² - u², where v will be 0 at max height
s = -(160)² / 2 x -32.174
s = 397.8 ft
b) Using:
s = ut + 1/2 at²
256 = 160t - 16.1t²
solving for t,
t = 2.0, t = 7.9
Now, v = u + at, for both times:
v(2) = 160 - 32.174(2)
v(2) = 95.7 ft/sec on the way up
v(7.9) = 160 - 32.174(7.9)
v(7.9) = -94.3 ft/sec; 94.3 ft/sec on the way down
c) -32.174 ft/s², which is the acceleration due to gravity.
d) s = 0
0 = 160t - 1/2 x 32.174t²
t = 9.94 seconds