Answer:
T=26.03 N
Explanation:
Given that
Distance between poles = 12 m
Mass of block m= 4 kg
Sag distance = 5 m
Lets take tension in the clothesline is T.
The component of tension in vertical direction will be T cosθ.
By force balancing
2 T cosθ = 40
here ![tan\theta =\dfrac{5}{6}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cdfrac%7B5%7D%7B6%7D)
θ=39.80°
2 T cos39.8 = 40
T=26.03 N
1. Magnetic properties of a substance depends on the structure of its valence electrons. It has something to do with orbitals so I suggest you study about molecular geometry of a compound/substance firstIt's the way a substance's atoms fit together, being pulled and pushed from all sides equally. exists in metallic bonds <span>if a substance is said to be magnetic, it is simply attracted by a magnet. if it is paramagnetic, it is repelled by a magnet.
2.</span>The magnetic field will be perpendicular to the electric field and vice versa<span>
An electric field is the area which surrounds an electric charge within which it is capable of exerting a perceptible force on another electric charge.
A magnetic field is the area of force surrounding a magnetic pole, or a current flowing through a conductor, in which there is a magnetic flux. A magnetic field can be produced when an electric current is passed through an electric circuit wound in a helix or solenoid.
The relationship that exists between an electric field and a magnetic field is one of electromagnetic interaction as a consequence of associating elementary particles.
The electrostatic force between charged particles is an example of this relationship.</span>
Answer:
ΔF=125.22 %
Explanation:
We know that drag force on the car given as
![F_D=\dfrac{1}{2}\rho C_DA v^2](https://tex.z-dn.net/?f=F_D%3D%5Cdfrac%7B1%7D%7B2%7D%5Crho%20C_DA%20v%5E2)
=Drag coefficient
A=Projected area
v=Velocity
ρ=Density
All other quantity are constant so we can say that drag force and velocity can be given as
![\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BF_D_1%7D%7BF_D_2%7D%3D%5Cdfrac%7Bv_1%5E2%7D%7Bv_2%5E2%7D)
Now by putting the values
![\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BF_D_1%7D%7BF_D_2%7D%3D%5Cdfrac%7Bv_1%5E2%7D%7Bv_2%5E2%7D)
![\dfrac{F_D_1}{F_D_2}=\dfrac{50^2}{75^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BF_D_1%7D%7BF_D_2%7D%3D%5Cdfrac%7B50%5E2%7D%7B75%5E2%7D)
![\dfrac{F_D_1}{F_D_2}=0.444](https://tex.z-dn.net/?f=%5Cdfrac%7BF_D_1%7D%7BF_D_2%7D%3D0.444)
Percentage Change in the drag force
![\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100](https://tex.z-dn.net/?f=%5CDelta%20F%3D%5Cdfrac%7BF_D_2-F_D_1%7D%7BF_D_1%7D%5Ctimes%20100)
![\Delta F=\dfrac{F_D_2-0.444F_D_2}{0.444F_D_2}\times 100](https://tex.z-dn.net/?f=%5CDelta%20F%3D%5Cdfrac%7BF_D_2-0.444F_D_2%7D%7B0.444F_D_2%7D%5Ctimes%20100)
![\Delta F=\dfrac{1-0.444}{0.444}\times 100](https://tex.z-dn.net/?f=%5CDelta%20F%3D%5Cdfrac%7B1-0.444%7D%7B0.444%7D%5Ctimes%20100)
ΔF=125.22 %
Therefore force will increase by 125.22 %.
Answer:
time rising = 34 / 9.8 = 3.47 sec
total time in air = 2 * 3.47 sec = 6.94 sec
(time rising must equal time falling)
R = 17 m/s * 6.94 s = 118 m
Can also use range formula
R = v^2 sin (2 theta) / g
tan theta = 34 / 17 = 2
theta = 63.4 deg
2 theta = 126.9 deg
sin 126.9 = .8
v^2 = 17^2 + 34^2 = 1445 m^2/s^2
R = 1445 * .8 / 9.8 = 118 m agreeing with answer found above