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3 years ago

15

A light bulb connects to a battery. A second, identical light bulb connects in parallel to the first light bulb. The connecting

wires have negligible resistance. When the switch is closed, the original light bulb will:
O no longer light.
O become brighter.
O become dimmer.
O experience no change in brightness.

1 answer:

mr Goodwill [35]3 years ago

8 0

Answer:d

Explanation:

Suppose V is the voltage of battery and R is the resistance of bulb

so Power drop for initial stage

$P_1=\frac{V^2}{R}$

When another identical bulb of same resistance is applied in parallel so voltage Drop across both the resistor will be same i.e. V

so Power consumed $P_2=\frac{V^2}{R}$

so there is no change in power and hence no dip in brightness

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Answer with Explanation:

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