Question

A light bulb connects to a battery. A second, identical light bulb connects in parallel to the first light bulb. The connecting wires have negligible resistance. When the switch is closed, the original light bulb will:
O no longer light.
O become brighter.
O become dimmer.
O experience no change in brightness.

Answer 1

Answer:d

Explanation:

Suppose V is the voltage of battery and R is the resistance of bulb

so Power drop for initial stage

$P_1=\frac{V^2}{R}$

When another identical bulb of same resistance is applied in parallel so voltage Drop across both the resistor will be same i.e. V

so Power consumed  $P_2=\frac{V^2}{R}$

so there is no change in power and hence no dip in brightness