Answer:
a) 37171
b) 
sec
Explanation:
m = mass of the weight being lifted = 60.0 kg
d = distance by which the weight is lifted = 0.670 m
E = Energy available to burn = 1 lb = 3500 kcal = 3500 x 4184 J
g = acceleration due to gravity = 9.8 m/s²
n = number of times the weight is lifted
Energy available to burn is given as
E = n m g d
3500 x 4184 = n (60) (9.8) (0.670)
n = 37171
b)
T = time period for each lift up = 1.80 s
t = total time taken
Total time taken is given as
sec
The change in internal energy of a system is given by (second law of thermodynamics)
where Q is the heat absorbed by the system and W is the work done on the system.
In order to correctly evaluate the internal energy change, we must be careful with the signs of Q and W:
Q positive -> Q absorbed by the system
Q negative -> Q released by the system
W positive -> W done on the system by the surroundings
W negative -> W done by the system on the surroundings
In our problem, the heat released by the system is
(with negative sign since it is released by the system), and the work done is
still with negative sign because it is performed by the system on the surrounding, so the change in internal energy is
Answer:
An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. ... A net force = unbalanced force. If however, the forces are balanced (in equilibrium) and there is no net force, the object will not accelerate and the velocity will remain constant.
Explanation:
Answer:
Potential energy will be 
Explanation:
We have given the height of the basin is h = 6 m
Area of the basin 
Volume 
Density 
We know that mass is given by 
We know that potential energy is given by 
