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4 years ago

6

I WILL GIVE INSTANT BRANLEST FOR WHO ANSERS THIS QUESTION CORECTLY The map of a walking trail is drawn on a coordinate grid with

three points of interest. The trail starts at R(−1, 4) and goes to S(5, 4) and continues to T(5, −2). The total length of the walking trail is ____ units. (Input whole numbers only.)

2 answers:

postnew [5]4 years ago

6 0

I believe it is 12 since it is not asking for shortest distance

Anna71 [15]4 years ago

4 0

Draw the trail and label all the points on the triangle.

Then, use the distance formula between points:

Distance = $\sqrt{(x1-x2)^2 + (y1-y2)^2}$

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3 years ago

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Answer:

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Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

$(x-h)^2+(y-k)^2=r^2$

Where the point (h,k) is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

$x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121$

Add 10x to both sides:

$x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121$

Make two groups for variable "x" and variable "y":

$(x^2+10x)+(y^2-20y)=-121$

Complete the square:

Add $(\frac{10}{2})^2=5^2$ inside the parentheses of "x".

Add $(\frac{20}{2})^2=10^2$ inside the parentheses of "y".

Add $5^2$ and $10^2$ to the right side of the equation.

Then:

$(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4$

Rewriting, you get that the equation of the circle in center-radius form is:

$(x+5)^2+(y-10)^2=2^2$

You can observe that the radius of the circle is:

$r=2$

And the center is:

$(h,k)=(-5,10)$

6 0

3 years ago

Read 2 more answers