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Pani-rosa [81]
4 years ago
6

I WILL GIVE INSTANT BRANLEST FOR WHO ANSERS THIS QUESTION CORECTLY The map of a walking trail is drawn on a coordinate grid with

three points of interest. The trail starts at R(−1, 4) and goes to S(5, 4) and continues to T(5, −2). The total length of the walking trail is ____ units. (Input whole numbers only.)

Mathematics
2 answers:
postnew [5]4 years ago
6 0
I believe it is 12 since it is not asking for shortest distance
Anna71 [15]4 years ago
4 0
Draw the trail and label all the points on the triangle.

Then, use the distance formula between points: 

Distance = \sqrt{(x1-x2)^2 + (y1-y2)^2}

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Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x
Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

(x-h)^2+(y-k)^2=r^2

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121

Make two groups for variable "x" and variable "y":

(x^2+10x)+(y^2-20y)=-121

Complete the square:

Add (\frac{10}{2})^2=5^2 inside the parentheses of "x".

Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

 (x+5)^2+(y-10)^2=2^2

You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

6 0
3 years ago
Read 2 more answers
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