Answer:
A) 62.37 x 10^(6) N
B) 59.86°
Explanation:
A) The magnitude of the force F1 due to the 0.062T magnetic field is;
F1 = |qo|(v)(Bx) Sin 90°
F1 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.062T = 53.94 x 10^(6) N
Also, the magnitude of the force F2 due to the 0.036T magnetic field is;
F2 = |qo|(v)(By) Sin 90°
F2 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.036T = 31.32 x 10^(6) N
Now, using Fleming's right hand rule, we will discover that the net force makes an angle with the x-axis. Let's call the angle θ. Since the forces will be at right angles to each other, then using Pythagoras theorem will get the resultant met force.
Thus;
F =√((F1)² + (F2)²) = √((53.94 x 10^(6))² + (31.32 x 10^(6))²)
= 62.37 x 10^(6) N
B) Since the forces are at right angles to each other, they are opposite and adjacent and since we know that tangent = opp/adj;
tan θ = F1/F2
tan θ = (53.94 x 10^(6)) / 31.32 x 10^(6) = 1.7222
Thus,θ = tan^(-1) 1.7222
θ = 59.86°
Answer:
yes it is possible for it to have a negative.
Answer:
The angular velocity of the wheel is 1080 rad/min.
Explanation:
Let the radius of the wheel is 16 inches. If the speed of the wheel is 24 ft/s. We need to find the angular speed of the wheel.
Since, 1 ft/s = 720 in/min
So, 24 ft/s = 17280 in/min
Let 
is the angular velocity of the wheel. It is given by :
So, the angular velocity of the wheel is 1080 rad/min. Hence, this is the required solution.
Jupiters gravitational pull is about 24.79 m/s to the second power.
Jupiters gravitational force is about 2.8 times stronger than Venus's.
Hope this helped
:D
