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vodka [1.7K]
2 years ago
12

An object is hanging by a string from the ceiling of an elevator. The elevator is moving upward with a constant speed. What is t

he magnitude of the tension in the string?
The magnitude of the tension in the string is equal to the magnitude of the weight of the object.
The magnitude of the tension in the string is less than the magnitude of the weight of the object.
The tension in the string cannot be determined without knowing the speed of the elevator.
The magnitude of the tension in the string is greater than the magnitude of the weight of the object.
The tension in the string is zero.
Physics
1 answer:
xeze [42]2 years ago
8 0

Answer:

The magnitude of the tension in he string is equal to the magnitude of the weight of the object.

Explanation:

According to the Newton's 1st law, An object will remain at rest or in uniform motion in a straight line unless acted upon by an unbalanced force.

In here, the elevator is moving with a constant speed. So the object must have the equal constant speed. Which means, it has a uniform motion. According to Newton's 1st law, the total unbalanced force on the object must be zero . As we know, there are only two forces are on the object and they are,

The tension in string(T)   ,   The weight of the object(W) .

                                  ∴ F    =   0

                                 T  -  W  =   0

So to balanced those forces, the magnitude of the tension in the string must be equal to the magnitude of the weight of  the object.  

       

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The electric flux is zero through four cube surfaces given that a cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

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Assuming the charged filament is quite long and you are not near the edges, the two opposing sides that the filament travels through have no flux. If the charge filament is long, which you may assume is indefinitely long, then there is the equal amount of charge on the left and right of where you are, therefore the electric field has no preference for left or right. This implies that the electric field can only travel in or out of the filament. No field lines run through the two faces of the cube that the filament goes through if the electric field is not moving left or right. There are electric field lines on the four sides of the filament.

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The food package will strike the ground at 11 degrees below the horizontal.

<h3>Time for the food package to hit the ground</h3>

The time for the food package to hit the ground is calculated as follows;

h = vt + ¹/₂gt²

<em>let the initial velocity be horizontal</em>

4900 = 0(t) + (0.5 x 9.8)t²

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<h3>Angle of projection</h3>

The horizontal component of the speed will be constant, while vertical component will change

tan(\theta ) = \frac{V_y}{V_x} \\\\\theta = tan^{-1} (\frac{V_y}{V_x})\\\\\theta = tan^{-1} (\frac{309.88}{58.1} )\\\\\theta = 79^0

Angle below the horizontal = 90 - 79 = 11⁰

Thus, the food package will strike the ground at 11 degrees below the horizontal.

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