Answer:
a.) $3.20
b.) $102.40
$3,276.80
Step-by-step explanation:
0.2 times 2 five times is 3.2
0.2 times 2 ten times is 102.4
0.2 times 2 fifteen times is 3,276.8
Answer:
law of cosines states c^2=a^2+b^2-2abc
b^2=26^2+24^2-2(26×24)cos 134°
b^2=676+576-1248cos134°
cos134= -0.6946
b^2=1252-12(-0.6946)
12×(-0.6946)= -8.3352
b^2=1252-(-8.3352)
b^2=1252+8.3352
b^2=1260.33
b=√1260.33
b=35.50
Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
Since we have given that
Integers between 10000 and 99999 = 99999-10000+1=90000
n( divisible by 3) = 
n( divisible by 5) = 
n( divisible by 7) = 
n( divisible by 3 and 5) = n(3∩5)=
n( divisible by 5 and 7) = n(5∩7) = 
n( divisible by 3 and 7) = n(3∩7) = 
n( divisible by 3,5 and 7) = n(3∩5∩7) = 
As we know the formula,
n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Answer:
z^ {8/5}
Step-by-step explanation:
