Y=2/3x + 7 in standard form
2 answers:
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I think you're factoring this...? You can do that by grouping here. Put the 4 terms in groups of 2 and factor out the greatest common factor. What's left behind is a common binomial factor that can also then be factored out. Like this:
Factoring what we can out of both sets gives us this:
The 2n-5 is a common factor between both the sets of terms, which in turn can also be factored out:
I'm not exactly sure what you are doing with this, but we can keep factoring for the sake of completeness. The 5 n-squared term can also be factored:
and 
and 
so 
. Simplifying that down its simplest is this:
So your three factors for that polynomial are
,
Factoring what we can out of both sets gives us this:
The 2n-5 is a common factor between both the sets of terms, which in turn can also be factored out:
I'm not exactly sure what you are doing with this, but we can keep factoring for the sake of completeness. The 5 n-squared term can also be factored:
So your three factors for that polynomial are