A farmer is enclosing a rectangular area for a pigpen. He wants the length of the pen to be 20 ft longer than the width. The far
mer can use no more than 100 ft of fencing. What is the pen’s greatest possible length? Let w represent the width of the pen. What expression represents the length?
Width is 15, length is 35.We can check our answer by multiplying the length by 2 and the width by two in order for the perimeter to be equal to 200.15 times 2 is 30 and 35 times two equals 70.70+30=100 so our solution satisfies our problem.
Step-by-step explanation:
Let the width be x.Then the length should be x+20.The farmer can’t use more than 100 ft of fencing and by mentioning enclosing a rectangle area for a pigpen, we can tell that 100 is the perimeter.So 2(x+20) + 2(x)=100.2x+ 40 + 2x=100.4x+40=100.4x=60.X is 15 which is the width so then the length is 35.
