Ask question

Ask question

All categories

kolbaska11 [484]

4 years ago

5

Solve for velocity in A car has traveled 456 meters in 45 seconds while driving east on Broad Street. What is the velocity of th

e car?

1 answer:

OLEGan [10]4 years ago

3 0

Answer:

10.13

Explanation:

take note that velocity is distance over time ( $v=\frac{d}{t}$ ) so you do 456(distance)÷45(time)= 10.13

You might be interested in

?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi

aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down. In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

4 0

3 years ago

In what substance would heat transfer by conduction work best? Oxygen, iron, water, or alcohol

hodyreva [135]

Iron is the answer. Becaues its solid and it's particles are closest to each other. And well.metals are good at transferring heat.

3 0

3 years ago

Read 2 more answers

A 30-kg shopping cart full of groceries sitting at the top of

Evgesh-ka [11]

Answer:

0.0102 m or 1 cm

Explanation:

Let g = 10m/s2

The potential energy of the shopping cart of the top of the hill is:

$E_p = mgh = 30*9.8*2 = 600 J$

When the cart gets to the bottom of the hill, all this potential energy is converted to kinetic energy:

$E_k = mv^2/2 = 600 J$

$v^2 = \frac{600*2}{30} = 40$

$v = \sqrt{39.2} = 6.324 m/s$

As the cart stop due to the stump, the can of peaches flies with the same speed.

By Newton's 3rd law, the car would exert a 490N force on the can too

The deceleration of the can would then be:

$a = F/m = 490/0.25 = 1960 m/s^2$

This force would stop the can, but not without making a dent, aka a traveled distance on the car skin

We can use the following equation of motion to find out the distance traveled by the can:

$v^2 - v_0^2 = 2a\Delta s$

where v = 0 m/s is the final velocity of the can when it stops, $v_0^2$ = 40m/s is the initial velocity of the can when it hits, a = -1960 m/s2 is the deceleration of the can, and $\Delta s$ is the distance traveled, which we care looking for:

$0 - 40 = 2*(-1960)*\Delta s$

$\Delta s = \frac{40}{2*1960} = 0.0102 m$ or 1 cm

3 0

3 years ago

A 1.2 g pebble is stuck in a tread of a 0.76 m diameter automobile tire, held in place by static friction that can be at most 3.

Maksim231197 [3]

Answer:

$v=33.764m/s$

Explanation:

Given data

Mass m=1.2 g=0.0012 kg

diameter d=0.76 m

Friction Force F=3.6 N

To find

Velocity v

Solution

From the Centripetal force we know that

$F_{c}=\frac{mv^{2} }{r}$

Where m is mass

v is velocity

r is radius

Substitute the given values to find velocity v

So

$F_{c}=\frac{mv^{2} }{r}\\v^{2}=\frac{F_{c}(r)}{m}\\ v=\sqrt{\frac{F_{c}(r)}{m}}\\ v=\sqrt{\frac{F_{c}(diameter/2)}{m}}\\v=\sqrt{\frac{(3.6N)(0.76/2)m}{(0.0012kg)}}\\v=33.764m/s$

4 0

3 years ago

You are standing against the wall near a corner of a large building. A friend is standing against the wall that is around the co

g100num [7]

Answer:

Sound Waves only needs a medium which in this case is Air,not withstanding the wall demarcation.

Explanation:

Sounds Waves can't be seen,they are Invisible.Anytime a person talks the produce vibration,and anytime you see vibration you are definitely seeing sounds.

You hearing your friend talk to you from the other compartment is made possible because their is a medium which in this case is Air.

Sound waves can travel in other medium apart from Air,Such Medium Includes Water and solids.

Air is invisible and when you talk you are sending sound waves into the air which in turn causes vibration which in this case you don't see but you can hear provided its of a reasonable pitch.

7 0

4 years ago