Her mass is still 70 kg
Explanation:
The mass of an object is an intrinsec property of the object that gives a measure of the "amount of matter" inside the object.
Being an intrinsec property, it depends only on the object itself, not on its location: therefore, the mass of an object is always the same in different locations. Therefore, the mass of the astronaut in the spacecraft is still the same as if she was on the earth, 70 kg.
On the contrary, the weight of an object is the force of gravity acting on the object, and it is given by

where
m is the mass
g is the acceleration of gravity
While m is always the same, the value of g changes based on the location: therefore, the weight of an object changes depending on the location.
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Unf there's no diagram. but this looks like a sort of celsius to fahrenheit temp scale conversion sort of problem.
Answer:
6 significant figure
Explanation:
The digits 111328 all are 6 figures with no figure being zero, neither zero after the other digits. In this case, all the numbers are significant and since they are only six numbers, then this is a six significant figure. In case we add another zero after digit 8, the zero is not significant but if added either infront of 8 or 2, the zero becomes significant.
Answer:
a) d = 30.79 m
, b) θ = -22.4°
, θ = 22.4 South of East
Explanation:
The easiest way to solve problems with vectors is to use their components, for this the East-West direction coincides with the x-axis and the North-South direction coincides with the y-axis
Let's use the index for / Ricardo and the index for Jane, let's break down the displacements
Richard
X axis
x₁ = 26.0 sin (60)
x₁ = -22.52 m
Y Axis
y₁ = 26.0 cos 60
y₁ = 13 m / s
Jane
X axis
x₂ = 16.0 cos (180 +30)
x₂ = -13.85 m
Y Axis
y₂ = 16.0 sin (180 + 30)
y₂ = - 8.0 m
Now we can use Pythagoras' theorem to find the distance between them
d = √ [(x₂ -x₁)² + (y₂ -y₁)²]
d = √ [(-13.85 + 22.52)² + (-8 -13)²]
d = 30.79 m
Let's use trigonometry to enter the address
tan θ = Δy / Δx
θ = tan⁻¹ Δy / Δx
θ = tan⁻¹ (-13.85 + 22.52) / (-8 - 13)
θ = tan⁻¹ (-8.67 / 21)
θ = -22.4°
The negative sign indicates that the angle is measured from the axis clockwise.
In the form of cardinal s point is
θ = 22.4 South of East
The answer is zero.
A simple harmonic motion has zero total mechanical energy as it moves beyond the equilibrium point, when it achieves the maximum displacement, when it moves past the equilibrium point, and when it moves past the equilibrium point and a non-zero constant.
What is simple harmonic motion?
- Simple Harmonic Motion (SHM) is a periodic, to and fro shifting rotation about the mean position of the body. The restoring force on an oscillating body is geared toward its mean direction since it is exactly proportional to its displacement.
- The sum of the potential energy and the kinetic energy constitutes the total energy in brainly.com/question/17315536.
- The particle's total mechanical energy when performing simple harmonic motion.
- The sum of the kinetic energy of the block plus the potential energy stored in the spring, which is proportional to the square of the amplitude, makes up the total energy of the block and spring system.
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