Answer: domain = 54 range = 14
Step-by-step explanation:
Amount of water in the pool at the end of the day is 5457798.7 gallons
<u>Explanation:</u>
Given:
Initial amount of water in the pool = 45,000 gallons
Increase in amount = 0.75 in per minute
Time, t = 1 day
t = 24 X 60 min
t = 1440 min
So,
Increase in amount of water in 1 day = 0.75 in X 1440
= 1080 in
Volume of 1080 in of water = (1080 in)³
Volume from cubic inch to gallon = 5453298.7 gallon
Amount of water in the pool at the end of the day = 45000 + 5453298.7 gallon
= 5457798.7 gallon
Step-by-step explanation:
I think the answer is B why don't you use a calculator?
Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
240
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5 48
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6 8
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3 2 4 2
