Ounces would be in the denominator of your ratio.
Converting ounces to pounds you would simply divide by 16 :)
Have a great rest of your day! Good luck!
solution:
3x-2y=1 , -9x-6y=-3.
solution system can be represent in (13,0) ( 1 3 , 0 ).
Answer:
(a)Revenue function,
Marginal Revenue function, R'(x)=580-2x
(b)Fixed cost =900
.
Marginal Cost Function=300+50x
(c)Profit,
(d)x=4
Step-by-step explanation:
<u>Part A
</u>
Price Function
The revenue function

The marginal revenue function

<u>Part B
</u>
<u>(Fixed Cost)</u>
The total cost function of the company is given by 
We expand the expression

Therefore, the fixed cost is 900
.
<u>
Marginal Cost Function</u>
If 
Marginal Cost Function, 
<u>Part C
</u>
<u>Profit Function
</u>
Profit=Revenue -Total cost

<u>
Part D
</u>
To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

The number of cakes that maximizes profit is 4.
Answer:
y=2/-1+8
Step-by-step explanation:
- -4= (-4,0) -4=x1 0=y1, 8= (0,8) 0=x2 8=y2
- formula is, y2-y1/x2-x1
- 8-0/0-4=8/-4=4/-2= 2/-1
- 2/-1 is the slope or (m), use (-4,0) or (0,8) i used (0,8) because its easier.
- (0,8), 0=x1 8=y1
- formula is y-y1=m(x-x1)
- y-8=2/-1(x-0) ---->distribute
- y-8=2/-1x-0 --->get y alone
+8 +8
- so the answer is y=2/-1+8
We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>