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3 years ago

Help with math please !

Mathematics

2 answers:

ioda3 years ago

6 0

Answer:

(-3,5)

Step-by-step explanation:

Darya [45]3 years ago

4 0

Answer:

x = - 3

y = 5

Step-by-step explanation:

x + y =2

x - y = -8

Cancel out both y's. Add x's and whole numbers to find x.

2x = - 6

Divide.

x = - 3

Insert - 3 into one of the equations. Solve for y.

- 3 + y = 2

Cancel out - 3 by adding 3 to both sides.

y = 2 + 3

Simplify.

y = 5

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Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x

valkas [14]

$\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k$
$\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)$

Let $\mathcal D$ be the region whose boundary is $\mathcal S$ . Then by the divergence theorem,

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV$

Convert to cylindrical coordinates, setting

$x=r\cos\theta$
$y=r\sin\theta$

and keeping $z$ as is. Then the volume element becomes

$\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$

and the integral is

$\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\dfrac{2\pi}3$

4 0

3 years ago

The length of time of the school field day was decreased

Tju [1.3M]

18% because take the first digits of each number and put them together lol

8 0

3 years ago

Chose all the values of x that are not in the domain of this rational function. Picture attached, 15 points and I'll give Brainl

pogonyaev

Answer:

All of them.

Step-by-step explanation:

For rational functions, the domain is all real numbers <em>except</em> for the zeros of the denominator.

Therefore, to find the x-values that are not in the domain, we need to solve for the zeros of the denominator. Therefore, set the denominator to zero:

$x(x-1)(x^2-4)=0$