Answer:
Time to land on 11ft is 4.25 seconds
Step-by-step explanation:
Given

Required
Solve for t when height is 11ft
This implies that 
So: substitute 11 for y in 

Collect Like Terms


Express both sides as squares


Take square roots of both sides (ignore negative)

Solve for t


Hence, time to land on 11ft is 4.25 seconds
Firstly arrange data from smaller to greater data point:
4 5 6 9 10 11 12 13 15 16
Secondly find the middle value: In our case the number of data is even, so to get the middle value we have to find the mean (average) between 10 & 11, that is 10.5. So the rank of the Median is10.5
Answer: its (0,2/3)
Step-by-step explanation: i say this because 2/3 equal 0.6 so 0.6 will be on the y-axis and 0 will be on the x-axis, this will equal a line that meats up wit R and is parallel to PQ. I hope this helps.
Answer:
Lon's Lawns
Step-by-step explanation:
32X9=288
25X10+50=300
21 chaperones are needed for 420 students.
Step-by-step explanation:
No. of juniors = 148
No. of seniors = 272
Total = 148+272 = 420 students
3 chaperones = 60 students
1 chaperone = 
Ratio of chaperon to students = 1:20
Let,
x be the number of chaperons for 420 students.
Ration of chaperones to students = x:420
Using proportion
Ratio of chaperones to students :: Ratio of chaperons to students

Product of mean = Product of extreme

Dividing both sides by 20

21 chaperones are needed for 420 students.
Keywords: ratio, proportion
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