Which of the following contribute(s) to most of the mass of an atom?

Drupady [299]

Answer is: The zooplankton can be used to help control algal growth in some coral communities.

Hypothesis is a suggested explanation for an observable phenomenon.

Steps of the scientific method:

1) ask a question about something that is observed.

2) do background research.

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested. In this example, does the presence of a certain type of zooplankton inhibited the algae growth

4) test of hypothesis.

5) analyze collected data and draw a conclusion. In this example, the zooplankton can be used to help control algal growth.

5 0

4 years ago

What is the pressure exerted by 68.0 g of nitrogen trihydride gas in a 50.0L container at 30.0 C?

Cloud [144]

Answer:

Molecular mass of NH3 = ( 14 + 3 ) = 17 g

$PV = \frac{m}{m _{r}} RT \\ P \times 50.0 \times {10}^{ - 6} = \frac{68.0}{17} \times 8.314 \times (30.0 + 273) \\ P = \frac{68.0 \times 8.314 \times 303}{17 \times 50.0 \times {10}^{ - 6} } \\ P = 2.02 \times {10}^{8} \: Pascals$

8 0

3 years ago

The positon of hydrogen is conversial in mendleevs perodic table give reason

Andreas93 [3]

The position of hydrogen is controversial in periodic table because hydrogen is the only element with out neutron. it belongs to 1 st group but it is not placed there .

6 0

3 years ago

Read 2 more answers

Units used in gas for pressure

Naya [18.7K]

Answer:

kilopascal, torr, and atmosphere

Explanation:

7 0

3 years ago

2 H2+O2=2 H2O

tia_tia [17]

Answer:

The percent yield is about 66.6%, but with sig figs it's 70%

Explanation:

The formula for percent yield is: (Actual Yield/Theoretical Yield) * 100

1. In order to solve for percent yield, you need both an actual and theoretical yield. This problem gives us an actual yield for H2O, which is 75 grams. Great, you're halfway there!

2. Next, you need to solve for the theoretical yield. In order to do so, you need to set up your stoichiometric ratio.

$100g O_{2} * (\frac{1 mol O_{2} }{31.998g O_{2} } )*(\frac{2 mol H_{2}O }{1 mol O_{2} } )*(\frac{18.015gH_{2}O }{1 mol H_{2}O } ) = 112.6g H_{2}O$

a) Take your given 100g of O2 and first convert it to moles

b) Then take the O2 in moles and create your mole-to-mole ratio. You're only given 2 values (75g of H2O and 100g of O2), so you know to use O2 and H2O in your ratio. The coefficients are essentially your ratio, so for H2O to O2 it's 2:1

c) Then convert the value from the mole-to-mole ratio back into grams to get your theoretical yield (as values from mole ratios are in moles)

3. Now that you have both your actual and theoretical yields, you can plug it into the equation and solve.

$\frac{Yield_{Actual} }{Yield_{Theoretical} } * 100$ = $\frac{75}{112.6}$ = 66.60403646

Which is 66.6% when rounded. With sig figs, again, it is 70%

5 0

3 years ago