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3 years ago

The following is an example of what type of chemical reaction?

1 answer:

4 0

This is a D. combustion reaction

That is because you add O2 which is necessary for a combustion, while the results are CO2 and water. What you are missing is a ---> after the 2O2 (g)

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Under conditions of "feasting", the body favors oxidation/utilization of which source for energy production

mezya [45]

During feasting, there is an increase in the supply of carbohydrates, fats and proteins in the body. Since these macronutrients are in excess, carbohydrates and proteins are utilized or oxidized as a source for energy production. On the otherhand, fats are accumulated as the rate of oxidation of this source does not increase during feasting.

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3 years ago

Read 2 more answers

EVIDENCE NOTEBOOK

BARSIC [14]

Answer:

Your body temperature would decrease

Explanation:

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2 years ago

The structure of cyclopentane-1,2-diol

Lady bird [3.3K]

Answer: five carbon atoms forms a ring. In adjacent two carbon atoms

An hydroxyl group (-OH) is attached. Molecular formula is

C5H8(OH)2

Explanation:

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2 years ago

What is the percent composition of water found in tin (IV) oxide octahydrate?

Tomtit [17]

Answer:

tin (IV) oxide octahydrate contains 8 part water

What is the percent composition of water found in tin (IV) oxide octahydrate?

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2 years ago

What mass of nitrogen monoxide is formed in the reaction of 869kg ammonia and 2480kg oxygen gas? (Please show work)

USPshnik [31]

Answer:

1533.6 kg NO

Explanation:

The reaction that takes place is:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert the masses of ammonia (NH₃) and oxygen gas (O₂) into moles, using their respective molar masses:

NH₃ ⇒ 869 kg ÷ 17 kg/kmol = 51.12 kmol NH₃

O₂ ⇒ 2480 kg ÷ 32 kg/kmol = 77.5 kmol O₂

77.5 kmol of O₂ would react completely with (77.5 kmol O₂ * $\frac{4kmolNH_3}{5kmolO_2}$ ) 62 kmol of NH₃. There are not as many kmol of NH₃, so NH₃ is the limiting reactant.

Now we calculate how many kmol of NO are produced, using the limiting reactant moles:

51.12 kmol NH₃ * $\frac{4kmolNO}{4kmolNH_3}$ = 51.12 kmol NO

Finally we convert kmol of NO to mass, using its molar mass:

51.12 kmol NO * 30 kg/kmol = 1533.6 kg NO

6 0

2 years ago