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natta225 [31]
3 years ago
9

describe in general terms an experiment to determine the molal freezing point depression constant kf of water. Assume the availa

bility of deionized water and solid NaNO3
Chemistry
1 answer:
Dvinal [7]3 years ago
6 0
A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point: 
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b -  molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.

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How many grams of barium sulfate can be produced from the reaction of 2.54 grams sodium sulfate and 2.54 g barium chloride? Na2S
Rama09 [41]

Answer: 2.796 grams

Explanation:

Na_2SO_4+BaCl_2\rightarrow 2NaCl+BaSO_4

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of sodium sulphate}=\frac{2.54g}{142g/mol}=0.018moles

\text{Number of moles of barium chloride}=\frac{2.54g}{208g/mol}=0.012moles

According to stoichiometry:

1 mole of BaCl_2 reacts with 1 mole of Na_2SO_4

0.012 moles of BaCl_2 will react with=\frac{1}{1}\times 0.012=0.012moles of Na_2SO_4

Thus BaCl_2 is the limiting reagent as it limits the formation of product. Na_2SO_4  is the excess reagent as (0.018-0.012)=0.006 moles are left unused.

1 mole of BaCl_2 produces 1 mole of BaSO_4

0.012 moles of BaCl_2 will produce=\frac{1}{1}\times 0.012=0.012moles of BaSO_4

Mass of BaSO_4=moles\times {\text {Molar mass}}=0.012\times 233=2.796g

Thus 2.796 grams of BaSO_4  are produced.

6 0
4 years ago
What is the percent composition of sodium (na) in baking soda
vagabundo [1.1K]

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Sodium                                           Na                                                          27.367%                  

4 0
3 years ago
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3 years ago
Two experiments were performed involving the following equilibrium. The temperature was the same in both experiments. H2(g) + I2
Leya [2.2K]
I believe that the best answer among the choices provided by the question is
<span>D.[HI] in experiment A equals 1/2[I2] in experiment B.</span>
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3 0
3 years ago
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A student loaded a mixture of compounds onto a silica gel column using 5 mL of dichloromethane as the loading solvent. After run
Ymorist [56]

Answer:

Petroleum ether was the incorrect eluant.

Explanation:

In column chromatography, there must be a mobile phase (eluant) and a stationary phase(adsorbent column). The mobile phase in this case is petroleum ether while the stationary phase is silica gel.

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4 years ago
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