132 g of C , 22 g of H , 176 g of O
132 + 22 + 176 => 330 g <span>of the substance
</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u H = 1.0 u O = 16.0 u
C = 132 / 12.0 => 11 moles
H = 22 / 1.0 => 22 moles
O = 176 / 16.0 => 11 moles
Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1
H = 22 / 11 => 2
O = 11 / 11 => 1
formula empirically <span>is : CH</span>₂O
hope this helps!
Answer:
The r.a.m. value is used to determine how many isotopes an element has.
Explanation:
Answer:
First of all, the equation is typed wrong so it can easily be misinterpreted
Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)
CH4 + 2O2 -----> CO2 + 2H2O
And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.
Reply:
Hi! What ch4t? i'd like to know ^^
