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VLD [36.1K]
2 years ago
11

Which number line shows the solution of 5x-8<-3

Mathematics
1 answer:
makvit [3.9K]2 years ago
5 0

Answer:

C

Step-by-step explanation:

It is right

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What is the next term of the geometric sequence?
Makovka662 [10]

Answer:

16

Step-by-step explanation:

In a geometric sequence you are just multiplying basically. To go from 36 to 24, you multiply by 2/3, and the same will be with the next term. When you multiply 24 by 2/3 you get 16.

6 0
2 years ago
If M=5x^2+7x-4 and N=-3x^2-4x+5, then M-N equals
Phantasy [73]

Answer:

8x² + 11x - 9

Step-by-step explanation:

M - N

= 5x² + 7x - 4 - 1(- 3x² - 4x + 5) ← distribute parenthesis by - 1

= 5x² + 7x - 4 + 3x² + 4x - 5 ← collect like terms

= 8x² + 11x - 9

4 0
3 years ago
Question 20 fast please
kipiarov [429]

Answer:

Square root of 4 is 2

so  1+\frac{[1+\sqrt{2x-1]}^2 }{4}=4

frac{[1+sqrt{2x-1]}^2 }{4}=3

so 1+sqrt{2x-1]}^2=12

so 1+sqrt{2x-1}=V12

sqrt{2x-1}=V12-1

2x-1=(V12-1)^2=12-2V12+1=13-2V12

2x=13+1-2V12

2x=14-2V12

x=7-V12

x=7-2V3

I put an attachment to explain better

   

Step-by-step explanation:

6 0
3 years ago
Which terms describe this shape? Choose all that apply.
Sonja [21]
The correct answer is rectangle
4 0
2 years ago
Read 2 more answers
A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after
Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: P(A)=P(A|B)P(B)+P(A|B')P(B')

Use the law of total probability to determine the probability of a parcel being late.

P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0
3 years ago
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