Question

A stone is thrown vertically downward with an initial speed of 12.0 m/s from the top of a

Answer 1

The question is incomplete; However, the height from which the stone is thrown is most likely to be what's required of the question

Answer:

See Explanation

Explanation:

Given

$Initial\ Speed, u = 12.0m/s$

$Time, t = 1.54\ s$

Required

Determine the height

This question will be answered using the following equation of motion;

$S = ut + \frac{1}{2}gt^2$

Take g as 9.8

This gives:

$S = 12 * 1.54 + \frac{1}{2} * 9.8 * 1.54^2$

$S = 12 * 1.54 + \frac{1}{2} * 9.8 * 2.3716$

$S = 18.48 + 11.62084$

$S = 30.10084$

$S = 30.1\ m$ (Approximated)

Hence; Height = 30.1m