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4 years ago

A stone is thrown vertically downward with an initial speed of 12.0 m/s from the top of a

1 answer:

6 0

The question is incomplete; However, the height from which the stone is thrown is most likely to be what's required of the question

Answer:

See Explanation

Explanation:

Given

$Initial\ Speed, u = 12.0m/s$

$Time, t = 1.54\ s$

Required

Determine the height

This question will be answered using the following equation of motion;

$S = ut + \frac{1}{2}gt^2$

Take g as 9.8

This gives:

$S = 12 * 1.54 + \frac{1}{2} * 9.8 * 1.54^2$

$S = 12 * 1.54 + \frac{1}{2} * 9.8 * 2.3716$

$S = 18.48 + 11.62084$

$S = 30.10084$

$S = 30.1\ m$ (Approximated)

Hence; Height = 30.1m

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4 years ago

What is the solar system composed of?

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3 years ago

Read 2 more answers

When the height of the cylinder increased by a factor five from 100 m to 500 m what happened to the sounders gravitational poten

Ivanshal [37]

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It increased by a factor of 5.

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3 years ago

Suppose you are planning a trip in which a spacecraft is totravel at a constant velocity for exactly six months, as measuredby a

Eva8 [605]

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t = t’ / t=t^'/√(1-(v)2/c2 )

where t= time for the moving observer (relative to the spacecraft, fixed on Earth) = 110 years.

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3 years ago

The electron density in copper is 8.49 × 1028 electrons/m3. When a 1.00 A current is present in a copper wire with a 0.40 cm2 cr

vichka [17]

Answer:

Drift velocity in m/s is $1.84 \times 10^{-8}\ m/s$ .

Explanation:

Formula for Drift Velocity is:

$u = \dfrac{I}{nAq}$

Where I is the current

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A is the area of cross section and

q is the charge of one electron.

We are given the following:

n = $8.49 \times 10^{28}\ electrons/m^3$

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A = 0.40 $cm^2$ = 40 $\times 10^{-4}$ $m^{2}$

We know that q = $1.6\times10^{-19} C$

Putting all the values to find drift velocity:

$u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s$

So, drift velocity in m/s is $1.84 \times 10^{-8}\ m/s$ .

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3 years ago