Answer:
a.After 
second Mr Comer's speed 
b.Distance travelled by Mr.Comer in seconds 
Explanation:
a. Lets recall our first equation of motion 
Now we know that 
, 
and
Plugging the values we have.
Then Mr.Comer's speed after sec 
b.
Lets find the distance and recall our third equation of motion.
So 
distance covered.
Dividing both sides with 2a we have.
Plugging the values.
So Mr.Comer will travel a distance of .
A decrease in mass will decrease an objects weight because
weight = mass x gravitational constant
Answer:
44.4 m/s
Explanation:
d = 80 m, t = 1.8 s, find v
d = v*t
v = d/t = 80/1.8 = 44.4 m/s
Given parameters:
First velocity = 2.50m/s
Time of travel = 3s
Second velocity = 1.50m/s
Unknown:
The displacement during the first interval = ?
Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.
Velocity = 
So;
Displacement = Velocity x Time taken
Now input the parameter for the first velocity and time of travel;
Displacement = 2.5 x 3 = 7.5m
The displacement id 7.5m
