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sergiy2304 [10]
3 years ago
13

24 POINTS

Physics
1 answer:
arsen [322]3 years ago
7 0
It is a good question !!

A wave of a wavelength of infinitesimal small meters !!
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What did hegel and kant have in common? they both were determined to disprove marxist theory. they both thought that only histor
Ira Lisetskai [31]

Answer:

The two philosophers furthermore seem to share the same conception of the conditions of human freedom. For Hegel as well as Kant, a theory of morality and political right devoted to advancing the cause of freedom must require more than just the absence of obstacles preventing the satisfaction of our animal passions.

Explanation:

Hope that help ;)

8 0
1 year ago
Suppose you increase your walking speed from 5 m/s to 14 m/s in a period of 3 s. What is your acceleration
kirza4 [7]
5-14 m/s in 3 seconds
a=vf-vi/t
a=14-5/3
a=9/3
a=3 m/s^2
4 0
3 years ago
An astronomer discovers a massive galaxy which has four nuclei. What is a likely explanation for a galaxy having more than one n
statuscvo [17]

The universe is made of a lot of galaxies. The likely explanation for a galaxy having more than one nucleus is that the galaxy must have swallowed several smaller galaxies that were its neighbors.

  • There are some reason behind the theory that the eating up of a galaxy is by another galaxy. The galaxy is said to have a  powerful past due to the fact  that a lot of smaller galaxies were eaten up.

The universe is known to have a very largest galaxy called the giant elliptical galaxy that is made up of about a trillion stars.

Learn more from

brainly.com/question/22885678

6 0
2 years ago
Visible light falls into wavelength ranges of 400-700 nm, for which 1 m = 1 × 10 9 nm . The energy and wavelength of light are r
Paul [167]

Answer:

E = 3.54 x 10⁻¹⁹ J

Explanation:

The energy of the photon can be given in terms of its wavelength by the use of the following formula:

E = \frac{hc}{\lambda}

where,

E = energy = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ Js

c = speed of light = 2.998 x 10⁸ m/s

λ =  wavelength of light = 560.6 nm = 5.606 x 10⁻⁷ m

Therefore,

E = \frac{(6.626\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{5.606\ x\ 10^{-7}\ m}\\

<u>E = 3.54 x 10⁻¹⁹ J</u>

7 0
3 years ago
Two transverse waves travel along the same taut string. Wave 1 is described by y1(x, t) = A sin(kx - ωt), while wave 2 is descri
Vadim26 [7]

Answer:

6) Wave 1 travels in the positive x-direction, while wave 2 travels in the negative x-direction.

Explanation:

What matters is the part kx \pm \omega t, the other parts of the equation don't affect time and space variations. We know that when the sign is - the wave propagates to the positive direction while when the sign is + the wave propagates to the negative direction, but <em>here is an explanation</em> of this:

For both cases, + and -, after a certain time \delta t (\delta t >0), the displacement <em>y</em> of the wave will be determined by the kx\pm\omega (t+\delta t) term. For simplicity, if we imagine we are looking at the origin (x=0), this will be simply \pm \omega (t+\delta t).

To know which side, right or left of the origin, would go through the origin after a time \delta t (and thus know the direction of propagation) we have to see how we can achieve that same displacement <em>y</em> not by a time variation but by a space variation \delta x (we would be looking where in space is what we would have in the future in time). The term would be then k(x+\delta x)\pm\omega t, which at the origin is k \delta x \pm \omega t. This would mean that, when the original equation has kx+\omega t, we must have that \delta x>0 for k\delta x+\omega t to be equal to kx+\omega\delta t, and when the original equation has kx-\omega t, we must have that \delta x for k\delta x-\omega t to be equal to kx-\omega \delta t

<em>Note that their values don't matter, although they are a very small variation (we have to be careful since all this is inside a sin function), what matters is if they are positive or negative and as such what is possible or not .</em>

<em />

In conclusion, when kx+\omega t, the part of the wave on the positive side (\delta x>0) is the one that will go through the origin, so the wave is going in the negative direction, and viceversa.

4 0
3 years ago
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